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wlad13 [49]
3 years ago
13

Find equation to this line​

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

the equation of this line is y= 1x+6

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Whats the answer to problem # 10 show me what u did please!
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I cant explan but i think only rectangular prisms.
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3 years ago
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Quadrilateral CDEF is dilated by a scale factor of į to form quadrilateral C'D'E'F'.
Kobotan [32]

Given:

CDEF is dilated by a scale factor of \dfrac{3}{4} to form the quadrilateral C'D'E'F'.

To find:

The measure of side E'F'.

Solution:

If a figure is dilated by a scale factor of k, then the side of dilated figure is k times of corresponding side of original figure.

CDEF is dilated by a scale factor of \dfrac{3}{4} to form the quadrilateral C'D'E'F'. So,

E'F'=\dfrac{3}{4}\times EF

From the given figure it is clear that EF=12. So,

E'F'=\dfrac{3}{4}\times 12

E'F'=9

Therefore, the measure of side E'F' is 9 units.

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3 years ago
Divide these polynomials. (8x³ + 2x² - 7x + 2) ÷ (2x - 1)
Novay_Z [31]

Answer:

The answer is letter A.

(8x³ + 2x² - 7x + 2) ÷ (2x - 1)

8x³ + 2x² - 7x + 2 ÷ 2x - 1

(2x-1)(4x²+3x-2)÷2x-1

cancel 2x-1 so that the answer is 4x²+3x-2.

6 0
3 years ago
Three roots of a fifth degree polynomial function f(x) are -2, 2, and 4 + i. Which statement describes the number and nature of
Juli2301 [7.4K]

We know that imaginary roots always come in pairs, so we already know 4 solutions

-2, 2, 4 + i and a pair of 4 + i

Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots

So for sure, we will have 3 real roots and 2 imaginary roots

Last option, f(x) has three real roots and two imaginary roots

3 0
3 years ago
In a chemistry lab, you have 2 vinegars. One is 5% acetic acid, and one is 6.5% acetic acid. You want to make 200 ml of a vinega
Iteru [2.4K]
We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f  -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
<span> <span> <span> we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
</span> </span>
Source:
http://www.1728.org/mixture.htm


8 0
3 years ago
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