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Sauron [17]
3 years ago
6

PLEASE HELP ME IVE BEEN ASKING FOR AN HOUR PLEASE

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

4

Step-by-step explanation:

Go up 1 and go right 3, repeat that pattern.

hoa [83]3 years ago
5 0

Answer:

c is equal to 4

Step-by-step explanation:

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Pls help dis is due tomorrow n I have a science project also due so pls help me
pantera1 [17]
List A
4+4y=8y
4 (y-1)= 4
4y+1=5y

List B
4y-4=y
4 (y+1)=5y
1+4y=5y
5 0
3 years ago
What are some solutions of the question 3x^2-5x+2=0?
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

3x²-5x+2=0

3x²-3x-2x+2=0

3x(x-1)-2(x-1)=0

(x-1)(3x-2)=0

either x-1=0 which gives x=1

or 3x-2=0

x=2/3

7 0
2 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
Can someone teach me how do this! Please and thanks!
Katyanochek1 [597]

Check the picture below.

6 0
2 years ago
Find the four arithmetic means between 100 and 135.
Ad libitum [116K]
114-121-128. i believe to be correct
5 0
3 years ago
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