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sammy [17]
3 years ago
13

A salesperson set a goal to earn $2,500 in August. She receives a base salary of $1,000 per month as well as a 20% commission fo

r all sales in that month. How many dollars of merchandise will she have to sell to meet her goal?
Mathematics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

$7,500

Step-by-step explanation:

The correct answer is:

Money needed from commission: $2,500 - $1,000 = $1,500

Percent equation: $1,500 = m × .20

Total merchandise to sell: $1,500 ÷ .20 = $7,500

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Write the equation that represents the relationship between n the number of triangles and p the perimeter of the figures formed.
Klio2033 [76]
1 triangle: 2*6 + 1*5

2 triangles: 2*6 + 2*5

3 triangles: 2*6 + 3*5

So for n triangles: p = 2*6 + n*5 = 12 + 5n
4 0
3 years ago
Read 2 more answers
2 = 4x. And. 36/a=6<br> X=? A=?
Furkat [3]
X= 0.5 A= 6. Hope this helps!
5 0
2 years ago
The exterior walls and roof of a barn are to be painted. The barn is in the shape of a rectangular prism, with an isosceles tria
vlada-n [284]

<u>Given:</u>

The rectangular prism has a length of 25 feet, a width of 10 feet and a height 55 feet.

The triangular prism has a base length of 25 feet, a height of 8 feet, and a prism height of 55 feet.

<u>To find:</u>

The total area to be painted.

<u>Solution:</u>

There are 4 external surfaces for the rectangular prism and 4 external surfaces for the triangular prism.

The rectangular prism has 4 rectangles out which there are 2 sets of similar rectangles.

There are two rectangles with lengths of 25 feet and widths of 10 feet while the other two rectangles have lengths of 55 feet and widths of 10 feet.

The area of a rectangle with a length of 25 feet and a width of 10 feet = 25(10)= 250 square ft.

The area of two such rectangles = 2(250) = 500 square feet.

The area of a rectangle with a length of 55 feet and a width of 10 feet = 55(10)= 550 square feet.

The area of two such rectangles = 2(550) = 1100 square feet.

The triangular prism has 2 triangles and 2 rectangles.

The triangles have base lengths of 25 feet and heights of 8 feet while the rectangles have lengths of 55 feet and heights of 14.8 feet.

The area of a triangle with a base length of 25 feet and a height of 8 feet = \frac{1}{2}(25)(8)= 100 square feet.

The area of two such triangles =2(100)= 200 square feet.

The area of a rectangle with a length of 55 feet and a width of 14.8 feet = 55(14.8)= 814 square feet.

The area of two such rectangles = 2(814) = 1628 square feet.

The total area to be painted =500+1100+200+1628 = 3128 square feet.

So an area of 3128 square feet is to be painted.

8 0
3 years ago
Explain how to find (f^-1)’(b), given that b=f(a).
Ganezh [65]

Answer:

(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)

Step-by-step explanation:

The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).

Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).

Replacing x with f⁻¹(x) in the above relation, you get ...

... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))

Putting your given values in this relation, you get

... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)

7 0
3 years ago
The 15th term of an arithmetic series is
RSB [31]

Answer:

-1557

Step-by-step explanation:

a+14d=143

a+12d=183

--------------------

2d= -40

d= -20

a=183+240=423

a(100th)= 423+99*-20=423-1980= -1557

I hope that help =)

7 0
2 years ago
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