Answer:
Jacqueline runs at 6.25 minutes per mile
Step-by-step explanation:
Here we have that the total training time for Jacqueline = 54 minutes
The time for which Jacqueline swims = 30 minutes
Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes
Therefore the equation for Jacqueline's speed = Distance/Time we have
Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute
Therefore Jacqueline's pace = 0.16 miles/minute
The equation for Jacqueline's pace in miles/minute is presented as follows
Jacqueline's pace in miles/minute = Time of running/Distance
Jacqueline's pace in miles/minute = 1/0.16 miles/minute = 6.25 minutes/mile.
The area is 15 14/64 which simplifies to 15 4/14 becuse you multiply width times length
Answer:
y > -5/4
Step-by-step explanation:
12 > -4y + 7
Subtract 7 from both sides:
5 > -4y
Divide both sides by -4 (remember to flip the sign when multiplying or dividing by a negative number):
-5/4 < y
Here's another way to solve it. First, add 4y to both sides.
12 + 4y > 7
Subtract 12 from both sides:
4y > -5
Divide by 4:
y > -5/4
