Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
50%
Step-by-step explanation:
If there are 4 parts to the spinner, 4 is the whole. Since there are 2 even numbers (2&4), the fraction would be 
, which is simplified to 
. And because could also turn into 
, the percentage is 50%.
Hope this helps :)
Answer:
In linear expresiion 3 is the coefficient
X will be the variable and -15 will be the constant term.
Answer:
$2.90
Step-by-step explanation:
The quantity of the 1st type of candy be x lb and that of the second type − y lb with the price of $ p/lb.
Then, x=5y/12 or y=2.4x.
The "total price" equation will be: 4.6x + 2.4xp = 3.4(x+2.4x).
Solving for p, we get p = $2.90.
