<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
The domain is the input (x) value. Since the equation is not provided with any input limit the answer is negative infinity to infinity.
The answer is the last choice.
If she works 40 hours getting paid $12 an hour she will get $480
Answer:
2 * 10 ^-4
Step-by-step explanation:
We need the first number to be between 1 and less than 10
.0002
2 * 10 ^ exponent
We move the decimal 4 places to the right. Since we move it to the right the exponent is negative and is the number of places we moved the decimal
2 * 10 ^-4
