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Alenkasestr [34]
3 years ago
7

Is y = 6/x proportional

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0

Answer:

inversely proportional

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Marcus earns money from feeding cats and answering emails. He earns $7 a week for each cat he feeds and $0.20 for each email he
Dmitry_Shevchenko [17]
A.
7 times number of cats=pay
if pay=49 then
7 times number of cats=49
divide both sides by 7
number of cats=7

da equaton can be
c=number of cats
7c=49

he fed 7 cats


B.

7c=49
divide both sides by 7
equality property of division
(7c)/7=49/7
math fact
(7/7)c=7
1c=7
identity property of division
c=7
identity property of multiplication
7 cats

C. 7 cats
4 0
3 years ago
The price of sneakers reduced $6 per week for 7 weeks. By how much did the price of the sneakers change over 7 weeks?
mylen [45]

Answer:

7(-6)=-42

After 7 weeks the price will be reduced by 7 times $6

Thus the price will be $42

8 0
3 years ago
Sarah is the oldest out of here four sisters. Her youngest sister is half her age. The 2 other sisters are twin and are 2 years
marusya05 [52]
Sarah is 14
The twins are 12
The youngest (n) is 7

14+(12+12)+7=45

n=7
7 0
3 years ago
(06.05) Neil is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect? graph of the function f of
schepotkina [342]
Given the stated equation we know that that quadratic formula has 2 as its degree. This meats it has 2 roots. A linear equation has a degree of 1. A linear equation has 1 root. To know if they intersect, the must have one root in common. To know this, solve the two equation simultaneously. If they result to an answer then they intersect. 
5 0
3 years ago
Read 2 more answers
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
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