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4 years ago

The tables show some input and output values:

Mathematics

2 answers:

horsena [70]4 years ago

8 0

Answer:

Hey the answer is B because as this person said one input has one output.

Step-by-step explanation:

Radda [10]4 years ago

3 0

A because one input can have only one output

You might be interested in

Is 5.787787778...a rational or irrational number? Explain.

Musya8 [376]

Irrational, because it is non-terminating and non-repeating!

7 0

4 years ago

Which expression doesn't belong? Why does it not belong? A. 7.9x B. 7.9 · (-10) C. 7.9 + x D. - 79

motikmotik

Answer:

C. 7.9 + x

Step-by-step explanation:

Given - A. 7.9x B. 7.9 · (-10) C. 7.9 + x D. - 79

To find - Which expression doesn't belong? Why does it not belong?

Proof -

As given

A. 7.9x

B. 7.9·(-10)

C. 7.9 + x

D. -79

As we can see that Option A, B, D are the multiple of 7.9 but Option C is not the multiple of 7.9

So, Option C does not belong here.

∴ we get

The correct answer is - C. 7.9 + x

7 0

3 years ago

Find the inverse of g(x)

borishaifa [10]

To find the inverse of function f(x), follow these steps.
1) Replace f(x) with y.
2) Switch x and y.
3) Solve for y.
4) Replace y with f^(-1)(x).

5 0

3 years ago

A contaminant is leaking into a lake at a rate of R(t) = 1700e^0.06t gal/h. Enzymes that neutralize the contaminant have been ad

olasank [31]

Answer:

16,460 gallons

Step-by-step explanation:

This is a differential equation problem, we have a constant flow of contaminant into the lake, but also we know that only a fraction of that quantity of contaminant remains because of the enzymes. For that reason, the differential equation of contaminant's flow into the lake would be:

$\frac{dQ}{dt} =1700exp(0.06t)*exp(-0.32t)\\\frac{dQ}{dt} =1700exp(-0.26t)\\$

Then, we have to integrate in order to find the equation for Q(t), as the quantity of contaminant in the lake, in function of time.

$\int\limits^0_t {dQ}=\int\limits^0_t {1700exp(-0.26t)dt}\\Q(t)=\frac{1700}{-0.26} exp(-0.26t)+C \\$

Now, we use the given conditions to replace them in the equation, in order to solve for $C$

$t_{0} =0\\Q_{0}=10,000\\Q_{0}=-6538exp(-0.26*0)+C\\C=10,000+6538=16538$

Then, we reorganize the equation and we replace t for 17 hours, in order to determine the quantity of contaminant at that time:

$Q_{t} =-6538exp(-0.26t)+16538\\Q_{17} =-6538exp(-0.26*17)+16538\\Q_{17} =16460 gallons$

3 0

3 years ago

Find the missing side of The Triangle

saul85 [17]

Step-by-step explanation:

By phythagorous theorem,

AC²=AB²+BC²

AC²=36+64

AC²=100

AC=root of 100

AC=10

7 0

3 years ago