Answer: Option D. 1,778
Solution:
Standard brick:
Width: w=3.625 in
Height: h=2.25 in
Length: l=7.625 in
Volumen of one standard brick: v
v=w*h*l
v=(3.625 in)*(2.25 in)*(7.625 in)
v=62.19140625 in^3
Pallet of bricks:
Side: s=4 feet
s=(4 feet)*(12 in / 1 feet)→s=48 in
Volume of a pallet of bricks: V=s^3
V=(48 in)^3
V=110,592 in^3
Number of bricks could be in a pallet: n
n=V/v
n=(110,592 in^3) / (62.19140625 in^3)
n=1,778.252119
n=1,778
sorry if this is wrong but i think the answer is 21
<span>To get the bigger number, divide by 2 the sum of the given sum of the numbers and their difference. In this case-
(226 + 200)/2 = 426/2 = 213.
To get the smaller number, divide by 2 the difference of the given sum of the numbers and their difference. In this case -
(226 - 200)/2 = 26/2 =13.
The two numbers are 213 and 13.
The bigger number is 213</span>
So we know that 22% of the mass off the chocolate bars is pecans, and that 4.5kg of pecans were used. To find the mass of nutty chocolate bars made with 4.5kg of pecans we can divide the 4.5 by 22 to find 1% of the weight of nutty chocolate bars produced, then multiply it by 100 to find the full weight in kg.
So 4.5/22= 0.205 (3dp), then 0.205x100=20.5kg of nutty chocolate bars produced.
Now to convert the kgs of chocolate bars to lbs, we multiply by 2.205 (as there is approximately 2.205 lbs to 1 kg).
So 2.205x20.5kg=45.203 lbs (3dp) of nutty chocolate bars produced on Tuesday.
