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3 years ago

Which expression is equivalent to 15+3x?

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

5 0

Answer:

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Step-by-step explanation:

Show a picture and I will help you.

You might be interested in

Please help me with this question. I will mark you brainliest.

solong [7]

Answer:

Option D : $153

This is how I got that:

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour or part thereof, so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is $51

But Mr. Anand hired three boats so we simply times 51 by 3 and get our solution to the problem:

Mr. Anand must pay $153 or Option D

~That's All Folks~

-Siascon

4 0

3 years ago

What is th GCF of 21 and 18

ZanzabumX [31]

Answer:

The answer is 3.

Explanation:

Factors of 18:

1, 2, 3, 6, 9, 18.

Factors of 21:

1, 3, 7.

The highest number that both sets contain is 3, so the GCF will be 3.

5 0

3 years ago

Read 2 more answers

Nevaeh went shopping for a new phone because of a discount sale. She multiplied the price of the phone by 0.95 to find the price

ella [17]

Answer:

95% off

Step-by-step explanation:

because the percent u times by the actual price is the percent u have off

3 0

3 years ago

The Insurance Institute for Highway Safety publishes data on the total damage caused by compact automobiles in a series of contr

erastova [34]

Answer: $Min : $750\ ,\ Q_1= \$800\ ,\ Median : \$925\ ,\ Q_3=\$1050\ ,\ Max: \$1100$

Step-by-step explanation:

The five -number summary consists of five values :

Minimum value , First quartile $(Q_1)$ , Median , Third Quartile $(Q_3)$ , Maximum value.

Given : The Insurance Institute for Highway Safety publishes data on the total damage caused by compact automobiles in a series of controlled, low-speed collisions.

The following costs are for a sample of six cars:

$800, $750, $900, $950, $1100, $1050.

Arrange data in increasing order :

$750,$800, $900, $950, $1050, $1100

Minimum value = $750

Maximum value = $1100

Median = middle most term

Since , total observation is 6 (even) , so Median = Mean of two middle most values ($900 and $950).

i.e. Median $=\dfrac{900+950}{2}=\$925$

First quartile $(Q_1)$ = Median of lower half ($750,$800, $900)

= $800

, Third Quartile $(Q_3)$ = Median of upper half ($950, $1050, $1100)

= $1050

Hence, the five-number summary of the total damage suffered for this sample of cars will be :

$Min : $750\ ,\ Q_1= \$800\ ,\ Median : \$925\ ,\ Q_3=\$1050\ ,\ Max: \$1100$

3 0

3 years ago

An arrow is shot vertically upward from a platform 20 ft high at a rate of 179ft / s * e When will the arrow hit the ground ? Us

MissTica

The height attained by the arrow is modelled as,

$h(t)=-16t^2-v_{\circ}t+h_{\circ}$

Given that the initial height is 20 ft and the initial velocity is 179 ft per second,

$\begin{gathered} v_{\circ}=179 \\ h_{\circ}=20 \end{gathered}$

Substitute the values,

$\begin{gathered} h(t)=-16t^2-(179)t+(20) \\ h(t)=-16t^2-179t+20 \end{gathered}$

When the arrow hits the ground its height will become zero,

$\begin{gathered} h(t)=0 \\ -16t^2-179t+20=0 \end{gathered}$

Applying the quadratic formula,

$\begin{gathered} t=\frac{-(-179)\pm\sqrt[]{(-179)^2-4(-16)(20)}}{2(-16)} \\ t=\frac{179\pm\sqrt[]{33321}}{-32} \\ t=\frac{179\pm182.54}{-32} \\ t=\frac{179+182.54}{-32},t=\frac{179-182.54}{-32} \\ t=-11.298,t=0.1106 \end{gathered}$

Since time cannot be negative, we have to neglect the negative value.

Thus, it can be concluded that the arrow will hit the ground after 0.1106 seconds approximately.

7 0

1 year ago