I think it might be 7 don't know what answers you may have but its a guess
1/2x + 3 = 2/3x + 1....multiply everything by the common denominator of 6
3x + 18 = 4x + 6
3x - 4x = 6 - 18
-x = - 12
x = 12 <====
multiplying by the common denominator will get rid of the fractions
X = (2^2)^(2.5)
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32
</span>y^(-3/2) = 125
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
89 divided by 7 + 46^2 = 2128.71428571...
I hope this helps!
Consecutive odd integers are 2 apart
they are x and x+2
the product (x times (x+2)) is 1 less than 4 times their sum
x(x+2)=-1+4(x+x+2)


![x^2+2x=8x+7 minus (8x+7) from both sides [tex]x^2-6x-7=0](https://tex.z-dn.net/?f=x%5E2%2B2x%3D8x%2B7%20minus%20%288x%2B7%29%20from%20both%20sides%20%5Btex%5Dx%5E2-6x-7%3D0)
factor
what numbers multliply to get -7 and add to get -6?
-7 and 1
(x-7)(x+1)=0
set equal to 0
x-7=0
x=7
x+1=0
x=-1
so the x can be 7 or -1
the other number (x+2) can be 7 or 1
test each
7 and 9
7(9)=-1+4(7+9)
63=-1+4(16)
63=-1+64
63=63
true
-1 and 1
-1(1)=-1+4(-1+1)
-1=-1+4(0)
-1=-1+0
-1=-1
true
the 2 integers can be 7 and 9 or -1 and 1 (both pairs of numbers work)