To make it easier just assume there is no decimal point then just work out the 32÷4 where we know that 4 goes into 32 8 times so you get 8 remember the decimal point and since it was one decimal place you will push the decimal over to the left of 8 and that is how you get 0.8
Answer:
The area of a circle is equal to pi times the radius squared so that means the radius of this circle is the square root of. 25!that means the radius is 5
<span><span>C=(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span><span>C=(<span>x0</span>,<span>y0</span>,<span>z0</span>)</span></span><span> and radius </span><span>rr</span>.
<span><span>(x−<span>x0</span><span>)2</span>+(y−<span>y0</span><span>)2</span>+(z−<span>z0</span><span>)2</span>=<span>r2</span></span><span>(x−<span>x0</span><span>)2</span>+(y−<span>y0</span><span>)2</span>+(z−<span>z0</span><span>)2</span>=<span>r2</span></span></span><span> </span>
Answer:
R = 10 cm
Step-by-step explanation:
The area of a spherical shape is given by :
![A=4\pi r^2](https://tex.z-dn.net/?f=A%3D4%5Cpi%20r%5E2)
Where
r is the radius of the sphere
ATQ,
One large bubble separates into four small bubbles so that the total area of the small bubbles is equal to the area of the large bubble.
The radius of each small bubble is 5 cm
Using the given condition,
![4\pi R^2=4\times (4\pi r^2)\\\\R^2=4r^2\\\\R=\sqrt{4r^2} \\\\R=2r\\\\R=2\times 5\\\\R=10\ cm](https://tex.z-dn.net/?f=4%5Cpi%20R%5E2%3D4%5Ctimes%20%284%5Cpi%20r%5E2%29%5C%5C%5C%5CR%5E2%3D4r%5E2%5C%5C%5C%5CR%3D%5Csqrt%7B4r%5E2%7D%20%5C%5C%5C%5CR%3D2r%5C%5C%5C%5CR%3D2%5Ctimes%205%5C%5C%5C%5CR%3D10%5C%20cm)
So, the radius of the large bubble is equal to 10 cm.