Q + d = 63....q = 63 - d
0.25q + 0.10d = 10.80
0.25(63 - d) + 0.10d = 10.80
15.75 - 0.25d + 0.10d = 10.80
-0.25d + 0.10d = 10.80 - 15.75
-0.15d = -4.95
d = -4.95/-0.15
d = 33 <=== 33 dimes
q + d = 63
q + 33 = 63
q = 63 - 33
q = 30 <=== 30 quarters
we know that
If two lines are parallel , then their slopes are the same
we will proceed to calculate the slope of each line to determine the solution.
The formula to calculate the slope m between two points of the line is equal to

<u>case N 1) </u>line AB
Let

substitute the values




therefore
<u>The line AB is not the solution</u>
<u>vase N 2)</u> line FG
Let

substitute the values




therefore
<u>The line EG is not the solution</u>
case N 3) line CD
Let

substitute the values




therefore
<u>The line CD is not the solution</u>
case N 4) line HJ
Let

substitute the values




therefore
<u>The line HJ is the solution</u>
therefore
<u>the answer is the option</u>
line HJ
Answer:
D
Step-by-step explanation:
:)
Answer:
the greatest common factor is 2
Answer:
28
Step-by-step explanation: