Answer:
x= -3
y= -5
Step-by-step explanation:
10y - 3x = -41
+
-5y + 3x = 16
10y + (-5y) = 5y
-3x + 3x = 0
-41 + 16 = -25
5y + 0 = -25
y = -25/5
y= -5
10y -3× = -41
(10×-5) - 3x = -41
- 3x = - 41 + 50
- 3x = 9
x = -3
<h3>
Answer: Choice A</h3>
- Domain: x > 4
- Range: y > 0
========================================================
Explanation:
We want to avoid having a negative number under the square root. Solving
leads to 
So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.
So in reality, the domain is x > 4.
-------------
The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.
We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression
is positive because positive/positive = positive.
Therefore, the range of the given equation is y > 0
-------------
The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).
Answer:
£
Step-by-step explanation:
£1 = €1.14 /
£
=144€=
£
3x-12>15
3x>15+12
3x÷3>27÷3
x>9
Answer: 1 .Thus for a graph to have an Euler circuit, all vertices must have even degree. The converse is also true: if all the vertices of a graph have even degree, then the graph has an Euler circuit, and if there are exactly two vertices with odd degree, the graph has an Euler path.
2. A graph has an Euler circuit if and only if the degree of every vertex is even. A graph has an Euler path if and only if there are at most two vertices with odd degree.
Step-by-step explanation:
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