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vovangra [49]
3 years ago
10

There are 90 monkeys in a zoo.

Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0
I think it would be 103
KonstantinChe [14]3 years ago
4 0

Answer:

66

Step-by-step explanation:

Well funny enough I think this is a twisted quiz coz directly the last statement says;24 like to eat both apples and bananas,so those that don't like both but like either of them is simply 90-24=66.

My thinking ,oops

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24+3/8w. W=1/2. I need help nowwwww
aleksklad [387]

Answer:

24 3/16

Step-by-step explanation:

To work out the question, you first have to replace the letter with its numerical value. In this case, W = ½

therefore it becomes,

24 + (⅜ ✖ ½)

24 + 3/16

= 24 3/16

I hope it helps

4 0
3 years ago
I need help boi a(c – b) = d c =
alexandr1967 [171]

Hello from MrBillDoesMath!

Answer:

c = d/a + b


Discussion:

I think the Question is missing a comma.  Assuming you are trying to find the value "c",

a(c-b) = d  =>                               divide both side by "a"

(c-b) = d/a =>                               add "b" to both sides

c-b + b = d/a + b =>                      as -b + b = 0

c = d/a + b




Thank you,

MrB

5 0
3 years ago
Given the similarity statement ΔHIJ ∼ ΔWXY, which angle corresponds with ∠X?
MArishka [77]

Answer:

b. angle I

Step-by-step explanation:

3 0
3 years ago
Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .
kogti [31]

Answer:

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if (x+y)^{2} = x^{2} + 2\cdot x\cdot y  + y^{2}. From statement, we must fulfill the following identity:

a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}

By Associative and Commutative properties, we can reorganize the expression as follows:

a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2} (1)

Then, we have the following system of equations:

x = a (2)

(b^{2}-1) = 2\cdot x\cdot y (3)

y = c (4)

By (2) and (4) in (3), we have the following expression:

(b^{2} - 1) = 2\cdot a \cdot c

b^{2} = 1 + 2\cdot a \cdot c

b = \sqrt{1 + 2\cdot a\cdot c}

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, a, b, c > 1. If a, b and c are prime numbers, then  2\cdot a\cdot c must be an even composite number, which means that a and c can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, b must be a natural number, which means that:

1 + 2\cdot a\cdot c \ge 4

2\cdot a \cdot c \ge 3

a\cdot c \ge \frac{3}{2}

But the lowest possible product made by two prime numbers is 2^{2} = 4. Hence, a\cdot c \ge 4.

The family of all prime numbers such that a^{2} + b^{2} + c^{2} -1 is a perfect square is represented by the following solution:

a is an arbitrary prime number. (1)

b = \sqrt{1 + 2\cdot a \cdot c} (2)

c is another arbitrary prime number. (3)

Example: a = 2, c = 2

b = \sqrt{1 + 2\cdot (2)\cdot (2)}

b = 3

4 0
3 years ago
If x=14, what is the value of 3(x + 5)?
gladu [14]

Answer:

57

Step-by-step explanation:

parentheses first then multiply by 3

5 0
3 years ago
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