A video game system and several games are sold for $652. The cost of the games is 3 times as much as the cost of the system. Fin
d the cost of the system and the cost of the games.
Cost of the video game system: $
Cost of the video game system: $
1 answer:
Answer:
The cost of the system is $163 and The cost of the games is $489
Step-by-step explanation:
∵ A video game system and several games are sold for $652
∵ The cost of the games is 3 times as much as the cost of the system
→ Assume that the cost of the system is $x
∵ The cost of the system = x
∴ The cost of the games = 3 × x = 3x
∵ The total cost of the system and the games = 652
→ Equate the sum of the cost of the system and the cost of the games
by 652
∴ x + 3x = 652
→ Add the like terms in the left side
∴ 4x = 652
→ Divide both sides by 4 to find x
∵
∴ x = 163
∵ The cost of the system = x
∴ The cost of the system is $163
∵ The cost of the games = 3x
∴ The cost of the games = 3(163) = 489
∴ The cost of the games is $489
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Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar
50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.
c)The expected number of grams to be eaten before encountering the first fragments :
s