Answer:
Explanation:
Dividends through year 1 to 5:
D1 = 2.15*(1+0.30)^1 = 2.80
D2 = 2.15*(1+0.30)^2 = 3.63
D3 = 2.15*(1+0.30)^2 * (1+0.18)^1 = 4.29
D4 = 2.15*(1+0.30)^2 * (1+0.18)^2 = 8.58
D5 = 2.15*(1+0.30)^2 * (1+0.18)^3 = 12.86
PV (D1) = 2.80
PV (D2) = 3.63 *PVIF = 3.63 * 0.87719 = 3.19
PV (D3) = 4.29 * 0.76947 = 3.30
PV (D4) = 8.58 * 0.67497 = 5.79
PV (D5) = 12.86 * 0.59208 = 7.62
Total of all PV's = 22.69
As part of PSM standards, hazards communication standards require employers of different companies who use hazardous, unsafe and life threatening chemicals "to check, evaluate, classify and label each of those chemicals". These standards are developed and established by OSHA (Occupational Safety and Health Organization).
Answer:
b. complement goods
Explanation:
Complement goods -
These are the type of goods , that are related to each other in a certain manner , is referred to as complement goods.
These type of good are also referred to as paired goods or associated goods .
In case of complement goods , if a person buys first good , then he might require the second good too.
These goods can even alters the prices of each other .
For example ,
people buying a CD player , need to buy the corresponding CD too , and hence ,
CD player and CD are complement goods.
Hence , from the given scenario of the question,
The correct option is b. complement goods .
A complementary good is a good whose use is related to the use of an associated or paired good. Two goods (A and B) are complementary if using more of good A requires the use of more of good B.
Increase<span> in systemic blood pressure, what mechanism </span>would increase GFR<span>? </span>
Answer: 
Explanation:
If r is the number of successes out of n trials , then the sample proportion of success = 
For binomial experiment , if the population probability of success p on a single trial is not given , then the best point estimate for probability of success p on a single trial is the sample proportion of successes.
i.e. a point estimate for the probability of success p on a single trial :
Hence, a point estimate for the probability of success p on a single trial =
