Answer:
The proof is detailed below.
Step-by-step explanation:
We will first prove that if H(x) is a differentiable function in [a,b] such that H'(x)=0 for all x∈[a, b] then H is constant. For this, take, x,y∈[a, b] with x<y. By the Mean Value Theorem, there exists some c∈(x,y) such that H(y)-H(x)=H'(c)(x-y). But H'(c)=0, thus H(y)-H(x)=0, that is, H(x)=H(y). Then H is a constant function, as it takes the same value in any two different points x,y.
Now for this exercise, consider H(x)=F(x)-G(x). Using differentiation rules, we have that H'(x)=(F-G)(x)'=F'(x)-G'(x)=0. Applying the previous result, F-G is a constant function, that is, there exists some constant C such that (F-G)(x)=C.
Answer:
15
Step-by-step explanation:
if EG is equal to 21 and EF is equal to 6, just subtract EF from EG to get the value of FG
All you have to do is add exponents when multiplying like monomials. So it's just 4^2
Answer:
I think it would be finding the quantity in each group.
Step-by-step explanation:
Because there would be more than 1 group. there is only one group. so you are trying to find the number of hours each person in the group will get.
i think that is right sorry if not.
Answer:
You would have a 9% chance of getting 3 correct on every answer
