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atroni [7]
2 years ago
7

HELP I REALLY REALLY NEED THIS HELP MEE SUPER EZ 28 POINTS I REALLY NEED THIS I DONT REALLY CARE IF ITS WRONG AT LEAST YOU TRY ;

)
43. A frequency table is shown for the height’s of 4th graders in a class at Riverbend Elementary School. What is the probability that a fourth grader in this class is44 inches tall?


46. A bag contains 4 red, 3 green and 2 blue marbles. What is the probability of selecting a green marble and then a blue marble assuming you replace the first marble?

48. Sam draws a card and replaces it 20 times from a standard deck of 52 cards. He draws 16 black cards and 4 red cards. What is the experimental probability of drawing a black card?

49. Mark has a six-sided number cube. Each side is numbered from 1 to 6. What is the probability, expressed as a ratio, that Mark will roll a 6?

50. How likely is it that you would pick a pink marble out of a bag of marbles that had green, blue, red, and yellow marbles?

The graph shows the number of tickets sold at a movie theater (x-axis) and the total cost in dollars (y-axis). Which coordinate pair shows the unit rate?

22. As low tide came in, the ocean dropped by a rate of 12 inches every 3 minutes. Write a rational # describing this rate.
Mathematics
1 answer:
Lesechka [4]2 years ago
4 0

Answer:

43. I'm not really sure about this one but here's what I got:

The average height of a 4th grader is 58 inches. (Maybe that'll help) Also if it's by the number of kids in the class....I would assume that there are at most 33 kids in the class....I'm not sure what it's asking...sorry :(

46. There are 8 total marbles so if you were selecting a green marble the probability of getting a green marble would be 3/8. If there are 2 blue marbles  then the probability would be 2/8 or 1/4

LINK: https://mathbitsnotebook.com/Geometry/Probability/PBIndependentDependent.html

48. In a deck of cards there are 26 black cards and 26 red cards. Number of event occurrences. Total number of trials. For example, if a dice is rolled 6000 times and the number '5' occurs 990 times, then the experimental probability that '5' shows up on the dice is 990/6000 = 0.165. That should help with this one

LINK:

https://explorable.com/experimental-probability

49. Since there are 6 sides and each side is a number 1-6, the probability of rolling a six is 1:6

50. This one is easy if you read the question right. There are no pink marbles....

I'm not that great with graphs

I hope this helped a little....some of the questions I didn't understand.

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lapo4ka [179]
What is the question? I don't understand please explain?
6 0
3 years ago
Pls help me, <br> Answer choices are :<br><br> A. 7<br> B. 30<br> C. 28<br> D. 49
WARRIOR [948]
I think 30 because I did all the equation and I got 30
4 0
2 years ago
Read 2 more answers
Find x in the following triangle pls solve it fast!! Correct answer will get brainliest!!!!
neonofarm [45]

Answer:

c=26

Step-by-step explanation:

So you would use the formula a^2+b^2=c^2

10^2+24^2=c^2

100+576=c^2

C^2=676

c=26

4 0
3 years ago
The planning committee at school has 10 members. Exactly four of these members are teachers. A four-person subcommittee with at
Kipish [7]

Answer:

865

Step-by-step explanation: The set of possibilities are:

Subcommittee  is of 4 people according to:

4  teachers    0 other member       total possibilities    1

3  teachers     1     teachers  C₄,₃  = 4   and  other member  6    6*4   =  24

2 teachers     2      C₄,₂  =  4!/2!  = 12    2 (om)    and  C₆,₂   =  6!/4!  = 30

30*12  = 360

1  teacher        3     (om)               4         and  C₆,₃ = 6!/3!   =  120

120*4  = 480

Total ways of committee    1  + 24  + 360 +  480  = 865

4 0
2 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
2 years ago
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