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atroni [7]
3 years ago
7

HELP I REALLY REALLY NEED THIS HELP MEE SUPER EZ 28 POINTS I REALLY NEED THIS I DONT REALLY CARE IF ITS WRONG AT LEAST YOU TRY ;

)
43. A frequency table is shown for the height’s of 4th graders in a class at Riverbend Elementary School. What is the probability that a fourth grader in this class is44 inches tall?


46. A bag contains 4 red, 3 green and 2 blue marbles. What is the probability of selecting a green marble and then a blue marble assuming you replace the first marble?

48. Sam draws a card and replaces it 20 times from a standard deck of 52 cards. He draws 16 black cards and 4 red cards. What is the experimental probability of drawing a black card?

49. Mark has a six-sided number cube. Each side is numbered from 1 to 6. What is the probability, expressed as a ratio, that Mark will roll a 6?

50. How likely is it that you would pick a pink marble out of a bag of marbles that had green, blue, red, and yellow marbles?

The graph shows the number of tickets sold at a movie theater (x-axis) and the total cost in dollars (y-axis). Which coordinate pair shows the unit rate?

22. As low tide came in, the ocean dropped by a rate of 12 inches every 3 minutes. Write a rational # describing this rate.
Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

43. I'm not really sure about this one but here's what I got:

The average height of a 4th grader is 58 inches. (Maybe that'll help) Also if it's by the number of kids in the class....I would assume that there are at most 33 kids in the class....I'm not sure what it's asking...sorry :(

46. There are 8 total marbles so if you were selecting a green marble the probability of getting a green marble would be 3/8. If there are 2 blue marbles  then the probability would be 2/8 or 1/4

LINK: https://mathbitsnotebook.com/Geometry/Probability/PBIndependentDependent.html

48. In a deck of cards there are 26 black cards and 26 red cards. Number of event occurrences. Total number of trials. For example, if a dice is rolled 6000 times and the number '5' occurs 990 times, then the experimental probability that '5' shows up on the dice is 990/6000 = 0.165. That should help with this one

LINK:

https://explorable.com/experimental-probability

49. Since there are 6 sides and each side is a number 1-6, the probability of rolling a six is 1:6

50. This one is easy if you read the question right. There are no pink marbles....

I'm not that great with graphs

I hope this helped a little....some of the questions I didn't understand.

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1: The local street cart sells bacon egg and cheese sandwiches for $2.50,
myrzilka [38]

Answer:

213 sandwiches

534 soft drinks

Step-by-step explanation:

system of equations, if you want better explanation, hmu in the comments.

6 0
3 years ago
ASAP HELP<br> This is due today so answer correct and I have attempt to do your best
Kamila [148]

Answer:

3)  x-axis: 1 unit

   y-axis: 10 units    

4) quadrant II

coordinates:  (-2, 4)

7) Quadrants I and IV; time is always positive , but temperature can be positive and negative

8) W = (-0.75, -1)

Step-by-step explanation:

3)  x-axis: 1 unit

   y-axis: 10 units    

4) quadrant II

coordinates:  (-2, 4)

7) Quadrants I and IV; time is always positive , but temperature can be positive and negative

8) W = (-0.75, -1)

5 0
2 years ago
a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel
adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

                             = 24000 - 750x + 2400x - 75x²

                             = 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

                                    = $ 150 + 165

                                    = $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0
2 years ago
3:20pm to 8:00 pm how many hour's is that
Alex
4 hours and 40 minutes
6 0
2 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
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