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igomit [66]
3 years ago
14

What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2

Mathematics
1 answer:
aev [14]3 years ago
4 0

For this case we must find the domain of the following function:

y = ln (x + 2)

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

x + 2> 0\\x> -2

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: x> -2

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Answer:

Part 1) -17\frac{8}{9} -----> -6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

Part 2) -15.11 ------> -12.48-(-2.99)-5.62

Part 3) -19\frac{8}{9} -----> -19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

Part 4) -201.65 -----> -353.92-(-283.56)-131.29

Part 5) 74 ------> 83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

Step-by-step explanation:

Part 1) we have

-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}

To calculate the subtraction convert the mixed numbers to an improper fractions

6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}

3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}

8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}

substitute

-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}

Convert to mixed number

-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}

Part 2) we have

-12.48-(-2.99)-5.62

To calculate the subtraction eliminate the parenthesis first

-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11

Part 3) we have

-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})

To calculate the subtraction convert the mixed numbers to an improper fractions

19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}

4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}

3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}

substitute

-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})

Eliminate the parenthesis

-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}

Convert to mixed number

-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}

Part 4) we have

-353.92-(-283.56)-131.29

To calculate the subtraction eliminate the parenthesis first

-353.92+283.56-131.29=-201.65

Part 5) we have

83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})

To calculate the subtraction convert the mixed numbers to an improper fractions

83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}

108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}

99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}

substitute

\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})

Eliminate the parenthesis

\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74

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