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3 years ago

Can someone solve 6÷2(1+2)

Mathematics

1 answer:

mamaluj [8]3 years ago

8 0

Answer: 9

Step-by-step explanation:

To solve this problem, we need to use our order of operations, or PEMDAS.

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

6÷2(1+2) [parenthesis]

6÷2(3) [multiply/divide from left to right]

3(3) [multiply]

Now, we know that the answer is 9.

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Write three expressions that are equivalent to 8x + 16.

anyanavicka [17]

Answer:

1 is 8x + 16 = 6x

Step-by-step explanation:

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Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri

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Answer:

The car uses less gas

They use the same amount of gas after $\frac{640}{7}$ miles

Step-by-step explanation:

Given

The table represents the car mileage

$y = -\frac{1}{5}x + 31$ --- The van

First, calculate the car's slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

From the table, we have:

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So, we have:

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$m = -\frac{1}{40}$

Calculate the equation using:

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$y = -\frac{1}{40}x + 1.5+13.5$

$y = -\frac{1}{40}x + 15$

$m = -\frac{1}{40}$ implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

$y = -\frac{1}{5}x + 31$ --- The van

By comparison to: $y = mx + b$

$m = -\frac{1}{5}$

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

$1/40 < 1/5$

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

$y = -\frac{1}{5}x + 31$ --- The van

$y = -\frac{1}{40}x + 15$ --- The car

Equate both

$-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15$

Collect like terms

$\frac{1}{40}x -\frac{1}{5}x =-31 + 15$

$\frac{1}{40}x -\frac{1}{5}x =-16$

Take LCM

$\frac{x - 8x}{40} = -16$

$\frac{- 7x}{40} = -16$

Solve for -7x

$-7x = -640$

Solve for x

$x = \frac{640}{7}$

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