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neonofarm [45]
3 years ago
9

The diameter of a circle is 6 cm find the circumference to the nearest tenth

Mathematics
2 answers:
Yanka [14]3 years ago
8 0

Answer:

28.3

Step-by-step explanation:

If this answer helped you then please like this and consider marking it as brainliest :)

Ivanshal [37]3 years ago
4 0

Answer:

18.85 cm

Step-by-step explanation:

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What is the answer to 2c-5=c+4
VikaD [51]
2c-9=c
-9=-c
9=c
Hope that helps!
4 0
3 years ago
Read 2 more answers
1. What is the degree form for 4π/9
nikklg [1K]
the answer should be about 80 degrees
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4 years ago
Solve for y 3x=2y+10
docker41 [41]

Answer:

y=3/2x - 5

Step-by-step explanation:

Subtract the 2y to move it to the other side

Subtract the 3x to move it to the other side

you get the equation of -2y=-3x + 10

Divide by -2

5 0
4 years ago
4( x+6)=-4(2x-9)+3x​
kupik [55]

Answer:

x=1.33 repeating or 1 1/3

Step-by-step explanation:

You take 4 and distribute to everything in the parentheses.

You also do the same for the -4.

After you distribute, you should get: 4x+24=-8x+36+3x

Then you combine like terms (the two x's on the right side of the equation.

You should then get: 4x+24=-5x+36

Next, you subtract 24 from the positive 24, to cancel it out, and the 36 to get 12.

Then, add 5x to the negative 5x, to cancel it out, and to the 4x to get 9x.

Finally, you divide 12 by 9 to get 1.33 repeating or 1 1/3.

4 0
3 years ago
An oil tanker can be emptied by the main pump in 5 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is
r-ruslan [8.4K]

Answer:

so the answer will be 1

Step-by-step explanation:

An oil tanker can be emptied by the main pump in 5 hours.

An auxilary pump can empty the tanker in 14 hours.

If the main pump is started at 7pm, when should the auxilary pump be started

so that the tanker is emptied by 11pm?

:

Let t = no. of hrs to run the Aux pump

:

The main pump will run 4 hr (7 - 11 pm)

:

Let the completed job = 1; (an empty Tanker)

:

The shared work equation

4%2F5 + t%2F14 = 1

Multiply equation by 70 to get rid of the equation, results:

14(4) + 5t = 70

56 + 5t = 70

5t = 70 - 56

5t = 14

t = 14%2F5

t = 2.8 hrs to run the aux pump

:

2.8 hr = 2 + .8(60) = 2 hrs 48 min

:

Subtract 2:48 from 11:00 = 8:12 PM start the aux pump

;

;

Check solution

4/5 + 2.8/14 =

.8 + .2 = 1

6 0
3 years ago
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