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konstantin123 [22]
3 years ago
8

Simplify the expression.

Mathematics
2 answers:
Scilla [17]3 years ago
6 0
The answer is -21-33i
N76 [4]3 years ago
6 0

For this case we have the following expression:

(-3 + 6i) (- 3 + 5i)

To solve the problem, we apply the distributive property.

We have then:

(9 - 15i) + (-18i + 30i ^ 2)

Rewriting we have:

30i ^ 2 -33i + 9\\30 (-1) -33i + 9\\-30 -33i + 9\\-33i - 21

Therefore, the answer for this case is:

-21-33i

Answer:

-21-33i

Note: review the options again. The answer does not seem to be among the options.

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A die is rolled one thousand times. The percentage of aces should be around ____ or so. the first step iin computing this proble
Katyanochek1 [597]

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

Box \ average =\frac{1}{6}  \\\\SD = \frac{1}{6}  \times \frac{5}{6} = \frac{5}{36} \approx 0.373\\\\Expected \ value= 1000 \times \frac{1}{6}  \approx 166.7\\\\SE = 1000 \times 0.373 \approx 11.8\\\\

The total number of aces is approximately 167, 12 or more. The SE is 12 out of 1000, which is 1.2 percent.

The percentage of aces is expected to be around 16.67% , or 1.2%.

7 0
3 years ago
Find the slope between (-4,1) and (-2,-2)
alukav5142 [94]

Answer:

-1.5

Step-by-step explanation:

y=-1.5x-5

7 0
3 years ago
Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12
BARSIC [14]

We are told that Christina collected information about the ages of the players on her softball team. The ages were 10, 12, 14, 13, 12, 11, 13, 12, 11, 12, 12, and 13. Christina wants to describe the players’ ages in an article for the school newspaper.

Since we know that range of a data is difference between the highest and lowest values of a data set. Range of our data set will be 4 (14-10). A group of different ages could have same range as Christina's data set. So range will be not a good option.

A measure of central tendencies will be better option to represent information about ages of softball team players. Mean will give the average age of softball players.

\text{Mean age of players}=\frac{10+11+11+12+12+12+12+12+13+13+13+14}{12}

\text{Mean age of players}=\frac{145}{12}=12.0833

Let us find median of data.

10,11,11,12,12,12,12,12,13,13,13,14        

\text{Median age of softball players}=\frac{12+12}{2}

\text{Median age of softball players}=\frac{24}{2}=12

We can see that average of our data is 12 years.    

Therefore, a measure of central tendency will be better choice to describe ages of softball players.      

7 0
3 years ago
Asher pays 156 every 6 weeks for piano lessons what is the price per year for piano lessons
Anna [14]
356 days in a year / 7 days in a week = 50.8 weeks in a year

50.8 weeks in a year / 6 weeks = 8.48 payments

$156 x 8.48 payments = $1322.88 per year
6 0
3 years ago
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
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