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Fittoniya [83]
3 years ago
14

Find the slope of the line containing the pair of the points. (-10,9) and (-6,-9)

Mathematics
2 answers:
pochemuha3 years ago
6 0

Answer:

i believe its -18/4 hope it helps

Step-by-step explanation:

zlopas [31]3 years ago
5 0

Answer:

-9/4

Step-by-step explanation:

putting these to y/x form it is 9/-10 and -9/-6 which has a difference of -9/4 (hopefully this is correct-)

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Can someone please explain this to me? I’m really confused on how to find the limit with the piecewise function.
ryzh [129]

Answer:   2

<u>Step-by-step explanation:</u>

You only need to evaluate at the limit point.

f(x) = 4 - x  ; x ≠ 2

Consider the solution if x = 2 (because the limit is x → 2)

                                          f(2) = 4 - (2)

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7 0
3 years ago
Let the vector \mathbf{v}v have an initial point at (1, -2)(1,−2) and a terminal point at (0, 0)(0,0). Plot the vector \mathbf{v
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Given that the initial point of the vector is (1,-2) and the termination point of the vector is (0,0).

So, the tail of the vector is at point (1,-2) and the head of the vector is at (0,0). The vector, \vec{v}, has been shown in the figure.

The magnitude of the vector:

|\vec{v}|=\sqrt{(1-0)^2+(-2-0)^2}=\sqrt{1+4}=\sqrt{5}

The direction of a vector is the angle made by a vector with the positive direction of the x-axis.

From the figure, \theta = 180 \degree\tan ^{-1} \left|\frac {0-(-2)}{0-1}\right|

\theta = 180 ^{\circ} - \tan^{-1}(2) = 180 ^{\circ} - 63.43^{\circ}

\theta =116.57 ^{\circ}

Hence, the required vector having a magnitude \sqrt {5} and direction 116.57 ^{\circ} has been shown in the figure.

4 0
3 years ago
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