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3 years ago

What is the domain of y=log5x

Mathematics

2 answers:

n200080 [17]3 years ago

7 0

The domain is x such that x >0<span>
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elixir [45]3 years ago

7 0

The domain is always x but I don't get the question you typed

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Paul needs to buy 5_8pound of peanuts. The scale at the store measures parts of a pound in sixteenths. What measure is equivalen

ryzh [129]

Answer:

10 ÷ 16

Step-by-step explanation:

The computation is shown below

Given that

Paul required to buy 5 by 8 pound of peanuts

And, the scale at the store is in sixteenths

So, the measure that should be equivalent is

Here the denominator should be 16 so it should be multiplied by 2

= 5 ÷ 8 × 2 ÷ 2

= 10 ÷ 16

3 0

2 years ago

How do you find the total sum of squared values?

tester [92]

Answer:

Step-by-step explanation:

$\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A$

$\sum_{r=3}^{12}= \sum_{r=1}^{12} - (r_1+r_2)$

$r_1= 1^2$

$r_2= 2^2$

you do your math!!

7 0

2 years ago

A couple quick algebra 1 questions for 50 points!

kirill [66]

All the relevant transformations are as shown in the explanations below.

<h3>How to Interpret Transformations?</h3>

We are given the original function as y = x and told the transformation is as follows;

1) y = x + 5; This means that the function was shifted 5 units to the left.

2) y = ³/₈x; This means that the function was vertically stretched by a scale factor of ³/₈.

3) y = -x - 2 or y = -(x + 2); This means that the function was first shifted by 2 units to the left before being reflected over the x-axis.

4) y = 6x + 1; This means that the function was stretched by a factor of 6 and then shifted 1 unit to the left.

5) y = x - 11; This means that the function was shifted 11 units to the right.

6) y = 8x; This means that the function was vertically stretched by a scale factor of 8.

7) y = -1/3x; This means that the function was horizontally stretched by a scale factor of 1/3.

Read more about Transformations at; brainly.com/question/4289712

#SPJ1

6 0

1 year ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

2 years ago

Write 110% as a mixed number in simplest form

tankabanditka [31]

Answer:

1 1/10

Step-by-step explanation:

110% = 110/100 = 11/10 = 1 1/10

5 0

2 years ago