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Akimi4 [234]
4 years ago
13

What is the domain of y=log5x

Mathematics
2 answers:
n200080 [17]4 years ago
7 0

 
The domain is x such that x >0<span>
</span>
elixir [45]4 years ago
7 0
The domain is always x but I don't get the question you typed
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Here are 7 numbers.
SIZIF [17.4K]

Answer:

3.06

I hope this helps you :)

4 0
3 years ago
Ryan records four numbers from his science homework using scientific notation.
lisabon 2012 [21]

\large \mathfrak{Solution : }

The incorrect one is 35 × 10⁵

it can be written as :

  • 3.5 \times 10 {}^{6}

8 0
3 years ago
What is the value of y?<br> y + 30
Musya8 [376]

you can't solve this nor find the value of y because its not a full equation

6 0
3 years ago
Read 2 more answers
If g x 3x 5 then g 1 x
Ray Of Light [21]
G(x) = 3x + 5
y = 3x + 5
3x = y - 5
x = (y - 5)/3

Therefore, g^-1(x) = (x - 5)/3
5 0
3 years ago
In △ABC , line AB is extended up to point E and line BC is extended up to D . The measure of some of the angles is given as; ∠BA
Over [174]

Answer:

\angle ACD = 130 ^\circ.

Step-by-step explanation:

\angle ABC and \angle EBC are supplementary angles. Their sum should be 180^\circ.  \angle EBC = 120^\circ \implies \angle ABC = 180^\circ - \angle EBC = 180^\circ - 120^\circ = 60^\circ.

The sum of the three angles in triangle \triangle ABC: (\angle ABC + \angle BAC + \angle ACB) should be equal to 180^\circ.

\angle ABC = 60^\circ and \angle BAC = 70^\circ \implies \angle ACB = 180^\circ - \angle ABC - \angle ACB = 180^\circ - 70^\circ - 60^\circ = 50^\circ.

\angle ACB and \angle ACD form another pair of supplementary angles. Their sum should also be 180^\circ. \angle ACB = 50^\circ \implies \angle ACD = 180^\circ - \angle ACB = 180^\circ - 50^\circ = 130^\circ.

8 0
4 years ago
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