Let x be the original radius. Given that a semicircle will have an arc length of half of a circumference and C=2pr, the arc length will be just pr.
Now the difference of arc is then going to be:
p(6+x)-px
p(6+x-x)
6p inches
So the arc will be 6p inches longer. Or if you wish to approximate...
≈18.85 inches
Answer:
circumference: 31.41593 ft
Area: 78.53982 ft
Step-by-step explanation:
<h3>
Answer: B) II and III</h3>
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Explanation:
Check out the diagram below.
On the left side shows ASA can be used to prove the triangles congruent. Note the color coding to see how the angles match up. Also note that the segment TR is between angles STR and SRT. The order is important because ASA is different from AAS.
Angle STR = Angle VTU because they are vertical angles
Angle SRT = Angle VUT since they are alternate interior angles. Note how SR is parallel to UV. If the lines weren't parallel, then the alternate interior angles would not be congruent.
We can use AAS because if we know two angles of a triangle, we can find the third angle. Despite the fact that something like RST looks like a right angle, we don't have enough info to say it is or not. The square angle marker is missing. So it could be 90 degrees, or it might be something like 89 degrees instead. We don't have enough info. So we cannot use HL.
AAA or AA is not a congruence theorem. It's a similarity theorem. So we cross this off the list.
Answer:
Option A
Step-by-step explanation:
A hunter travels to his cabinet located at 2 Miles North and 8 Miles West.
Let "d" be the distance traveled before reaching the rocky ground at point say "P". Let the cabin be at "C"
The distance between C and P is given by

Let "t" be the time taken to travel distance CP.

Minimum time will be when "t" is equal to zero
Differentiating the above equation wrt "d", we get -

On squaring both the sides , we get -

"d" cannot be greater than 8 miles.
Hence, the value of "d" is equal to 
Option A