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REY [17]
3 years ago
15

Different machines pack boxes. Which ratio represents each of the machines?

Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

HI

Step-by-step explanation:

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Picture shown please help !!!
natulia [17]
Let's factor the top and the bottom.
Top factors 4x + 20 = 4(x + 5)
Bottom x^2 + 2x - 15 = (x + 5)(x - 3)

The gcf is the largest value that will go into both the top and the bottom.  In our problem the ONLY thing that will go into top and bottom is x + 5 so that is your GCF. (c)
4 0
3 years ago
Which of the binomials below is a factor of this trinomial x^2+4x-60
trasher [3.6K]

Suppose x-6 is listed as a possible answer. That is zero if x = 6. So put x=6 into the original x^2 + 4x - 60 to get 6^2 + 4*6 - 60 = 36 + 24 -60 = 0. hence x-6 is a factor.

Answer (x-6)

on this hand :x-5 is not a factor, because plugging x=5 into does not work.

6 0
3 years ago
What does 2 equal as a fraction
vichka [17]
2/1 is the fraction always as a whole number the whole number goes on top and always the 1 goes on bottom for every whole number Hope that helped have a good day! :)

7 0
3 years ago
Read 2 more answers
I’m confused on what to do next please help
Mekhanik [1.2K]

Answer:

There are 585 adults and children

Step-by-step explanation:

Let the number of adults be a, number of children be c and the number of seniors be a

Amount made per group;

adults; 52 * a = 52a

Children : 26 * c = 26c

Seniors = 20 * s = 20s

Adding all will give 20,490

52a + 20s + 26c = 20 490 ••••(i)

Now let us work with the ratios;

a : s = 6 : 1

a/s = 6/1

a = 6s •••••(ii)

Lastly;

a/c = 4/9

4c = 9a ••••(ii)

We want to get a + c

From the first equation , let’s substitute

52(6s) + 20s + 26c = 20,490

26c = 6.5 (4c)

but 4c = 9a; 6.5(9a)

But a = 6s

So we have; 6.5(9)(6s) = 351s

so we have;

312s + 351s + 20s = 20,490

683s = 20,490

s = 20490/683

s = 30

Recall;

a = 6s = 6 * 30 = 180

4c = 9a

4c = 9 * 180

c = (9 * 180)/4 = 405

So the total number of children and adult is a + c

405 + 180 = 585

3 0
2 years ago
Someone pls help me with this​
katrin2010 [14]
I need help with it too!
5 0
3 years ago
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