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Ulleksa [173]
3 years ago
13

Magnesium has two naturally occurring isotopes: magnesium-24 and magnesium-25. if the average atomic mass of magnesium is 24.305

amu, what are the percent abundance's of each isotope?
a. 69.5% and 30.5%
b. 50% and 50%
c. 62% and 38%
d. 0.7% and 0.3%
e. .62% and .38%
Chemistry
1 answer:
tatuchka [14]3 years ago
3 0

Answer:

a. 69.5% and 30.5%

Explanation:

we know there are two naturally occurring isotopes of Mg, Mg-24  and Mg-25.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 25

1-x for isotopes having mass 24

The average atomic mass of Mg is 24.305 amu.

we will use the following equation,

25x + 24 (1-x) =  24.305

25x + 24 - 24x =  24.305

25x- 24x = 24.305 - 24

1x = 0.305

x= 0.305 /1

x= 0.305

0.305 × 100 = 30.5 %

30.5 % is abundance of Mg-25 because we solve the fraction x.

now we will calculate the abundance of Mg-24.

(1-x)

1-0.305 =0.695

0.695  × 100 = 69.5%

69.5%   for Mg-24.

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mole fraction = 0.047

Explanation:

The complete question is

Calculate the molarity and mole fraction of acetone in a 1.09-molal solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

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1.09 / (1.09 + 21.71) = 0.047

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