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kifflom [539]
3 years ago
14

Predict whether each of the following bonds is ionic, polar, covalent, or nonpolar covalent:

Chemistry
2 answers:
uysha [10]3 years ago
8 0

Predict whether each of the following bonds is no polar covalent, polar covalent, or ionic

Bond. Electro negativity Type of bond

Si- O

k-Cl

I-I

C-H

Gekata [30.6K]3 years ago
7 0

Explanation:

It is known that in order to determine a compound to be ionic, polar, covalent or non-polar covalent it is necessary to determine the electronegativity difference of the combining atoms.

So, when electronegativity difference is from 0.0 to 0.4 then bond formed between the two atoms is non-polar covalent in nature.

When electronegativity difference is greater than 0.4 and less than 1.8 then bond between the two atoms is a polar covalent bond.

When electronegativity difference is 1.8 or greater than the bond formed is ionic in nature.

Electronegativity difference of the given molecules is as follows.

Si-O = (1.90 - 3.44) = 1.54

K-Cl = (0.82 - 3.16) = 2.34

S-F = (2.58 - 3.98) = 1.4

P-Br = (2.19 - 2.96) = 0.77

Li-O = (0.98 - 3.44) = 2.46

N-P = (3.04 - 2.19) = 0.85

Therefore, given compounds are classified as follows.

Si-O, S-F, P-Br, and N-P all have a polar covalent bond. Whereas K-Cl and Li-O are ionic in nature.

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How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.
Gekata [30.6K]

The reaction is given as

Fe2O3 (s)+ 3CO(g)--->3CO2(g)+ 2Fe(s)

No.of moles=mass in gram/molar mass

As for Fe mole =156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed= 2.797x3/2=4.1955

Mass of CO needed= 4.195mol x 28.01g/mol= 117.515g

8 0
3 years ago
Consider a gas in a container that can adjust its volume to maintain constant pressure. Suppose the gas is cooled. What happens
NNADVOKAT [17]

Answer:

The volume will also decrease.

Explanation:

This illustration clearly indicates Boyle's law.

Boyle's law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature, provided the pressure remains constant. Mathematically, it is represented as:

V & T

V = KT

K = V/T

V1/T1 = V2/T2 =... = Vn/Tn

Where:

T1 and T2 are the initial and final temperature respectively, measured in Kelvin.

V1 and V2 are the initial and final volume of the gas respectively.

From the illustration above, the volume is directly proportional to the temperature. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume also will decrease.

4 0
3 years ago
What is the volume of the liquid in the this diagram?<br>Would it be 37 mL or 36.5 mL?
vivado [14]

The volume of the liquid in this diagram shown above would be equal to 36.5 mL.

<h3>What is a graduated cylinder?</h3>

A graduated cylinder is also known as measuring cylinder and it can be defined as a narrow, cylindrical piece of laboratory equipment with marked lines, which are used to measure the volume of a liquid.

In order to take a reading for the measurement of the volume of a liquid such as water, you should ensure that your eye level is even with the center of the meniscus.

In this scenario, the volume of the liquid in this diagram would be 36.5 mL because each of the small lines on the graduated cylinder measures 0.5 mL.

Read more on graduated cylinder here: brainly.com/question/24869562

#SPJ1

8 0
2 years ago
A reaction that breaks large molecules into smaller ones by the addition of water is called a(n):
Luda [366]
Answer:  "condensation reaction" .
__________________________________________________
5 0
3 years ago
How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i
bagirrra123 [75]

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O  

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

7 0
3 years ago
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