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notka56 [123]
3 years ago
9

Helppppppp pleaseeeeee

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
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15mm

Step-by-step explanation:

we are looking for extension

To get Extension you need the original length and the strain both of which you are given

initial length L = 1.00m

the area A = 0.5mm² = 0.5 mm² = 0.5 x 10⁻⁶ m² ( we are changing to metres squared)

E = 2.0 x 10¹¹ n/m², Young's modulus

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Now to Calculate the stress.

σ = P/A (force/area) = (1500 N)/(0.5 x 10⁻⁶ m²) = 3 x 10⁹ N/m²

Also, Let β =  the stretch of the string.

Then the strain is

ε = β/L (extension/ original length)

By definition, the strain is ε = σ/E = (3 x 10⁹ N/m²)/(2 x 10¹¹ N/m²) = 0.015

Therefore β/(1 m) = 0.015β = 0.015 m = 15 mm

Answer:  15 mm

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