0.009 = 9.10⁻³
hope this helps!
<em>Answer:</em>
- Such a alkane has only one ring that is cyclooctane.
<em>Explanation:</em>
- The general formula of alkane is CnH2n+2. Such general formula is applicable for only open chain alkane.
- When alkane form ring, then this formula does not remain valid.
- The general formula of Cycloalkane is CnH2n.
As in this case, there are 8-carbon and 16-hydrogen that is according to above cycloalkane formula.
Answer:
4.55 mol of C₂H₂
Explanation:
Let's verify the reaction:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Ratio is 1:1, so 1 mol of calcium carbide will produce 1 mol of acetylene.
4.55 mol of CaC₂ will make the same amount of C₂H₂
Percent yield is 108.3%
<u>Explanation:</u>
Percent yield is the ratio of experimental yield and the theoretical yield multiplied by 100.The expression for the percent yield is given as,
Percent yield =
It is given that the experimental or actual yield is 3.9 g and the theoretical yield calculated using stoichiometry is 3.6 g, then the percent yield is calculated as,
Percent yield =
So the percent yield is 108.3%.
The question is incomplete. Complete question is attached below.
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Correct Answer: Option D i.e. 34.8 gReason:
Molecular weight of HgS = 232.66 g/mol
Atomic weight of Hg = 200.59 g/mol
Thus, 200.59 g Hg ≡ 232.66 g of HgS
Therefore, 30 g of Hg ≡
= 34.8 g
Thus,
34.8 g HgS would contain 30 g mass percent of Hg