Answer:
8
Explanation:
From the question given above, the following data were obtained:
t–butyl ion = (CH₃)₃C⁺
Number of valence electron =?
The valence electron(s) talks about the combining power of an element or compound as the case may be.
Considering the t–butyl ion, (CH₃)₃C⁺ we can see that it has a charge of +1 indicating that it has given out 1 electron to attain the stable octet configuration which has a valence electrons of 8. Thus, the valence electron of t–butyl ion, (CH₃)₃C⁺ is 8
Methane CH4 CH4 1 hexane C6H14 CH3(CH2)4CH3 5
ethane C2H6 CH3CH3 1 heptane C7H16 CH3(CH2)5CH3 9
propane C3H8 CH3CH2CH3 1 octane C8H18 CH3(CH2)6CH3 18
butane C4H10 CH3CH2CH2CH3 2 nonane C9H20 CH3(CH2)7CH3 35
pentane C5H12 CH3(CH2)3CH3 3 decane C10H22 CH3(CH2)8CH3 75
put 8 in front of the oxygen in the reactants side to make it 16 molecules then put a 5 in front of the co2 in the product side to balance the carbon atoms then put a 6 in front of the H20 on the product side this balances both the hydrogen and oxygen atoms here is a representation
C5H12(g)+8O2(g)=5CO2(g)+6H20
Answer:
characteristics i believe
Answer:
4.4g
Explanation:
Mass of CaCO3 = 10g
Mass of CaO = 5.6g
Mass of CO2 =?
Mass of CaCO3 = Mass of CaO + Mass of CO2
Mass of CO2 = Mass of CaCO3 — Mass of CaO
Mass of CO2 = 10 — 5.6
Mass of CO2 = 4.4g
