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Firdavs [7]
2 years ago
9

Please help me i really need help please

Mathematics
2 answers:
Nutka1998 [239]2 years ago
8 0

Answer:

(2,4)

Step-by-step explanation:

ra1l [238]2 years ago
6 0

Answer:

d

Step-by-step explanation:

2,4

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Answer: 10.63

Step-by-step explanation: 8.1 + 2.53

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2 years ago
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Solve the systems equations for x and y and check:<br> y=2x+10<br> x=3y
andriy [413]
For Y=2x+10 X=y/2 -5. Second x/3
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2 years ago
Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)
DiKsa [7]

Answer:

C

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. y'=(3\sin x)'=3\cos x. Differentiate again to get y''=(3\cos x)'=-3\sin x, then y''+y=-3\sin x+3\sin x=0\neq 3\sin x so this choice of y doesn't solve the equation.

B. y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x and y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x, then y''+y=10\sin x+6\cos x\neq 3\sin x so y is not a solution

C. y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x hence y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x. Then y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x so y is a solution.

D.y'=-3\sin x and y''=-3\cos x, then y''+y=0 thus y isn't a solution

E. y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x hence y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x. Then y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x then y is not a solution.

3 0
3 years ago
Could a triangle be constructed with side lengths 4 cm, 5 cm and 13 cm? *​
Ratling [72]

Answer:

NO.

Step-by-step explanation:

No because 13 > 4 + 5.

7 0
3 years ago
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Step-by-step explanation:

hi im not really sure if this is right

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