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topjm [15]
3 years ago
6

Can you help me with this? (I will give one of you brainliest)

Mathematics
2 answers:
Degger [83]3 years ago
8 0

Answer:

1) \sqrt{9} and \sqrt{16} (between 3 and 4)

Explanation: \sqrt{9} and \sqrt{16} are the closest WHOLE squares root to \sqrt{12}; any other square roots wouldn't give us a whole number, or they're farther away from

2) -\sqrt{144} and -\sqrt{169} (between -(12) and -(13))

3) -\sqrt{36} and -\sqrt{49} (between -(6) and -(7))

Juli2301 [7.4K]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Consider perfect squares on either side of the radicand

(a)

9 < 12 < 16 , then

\sqrt{9} < \sqrt{12} < \sqrt{16} , so

3 < \sqrt{12} < 4

(b)

- 144 <  - \sqrt{158} < - 169

- \sqrt{144} < - \sqrt{158} < - \sqrt{169} , s0

- 12 < - \sqrt{158} < - 13

(c)

- 36 < - \sqrt{40} < - \sqrt{49} , so

- 6 < - \sqrt{40} < - 7

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