She graphed it correctly.
The inequality is the same as
after dividing both sides by 3 to isolate y.
From here you graph which is a straight line through (0,0) and (3,2). This line is made solid because of the "or equal to" as part of the inequality sign above.
We shade below the solid boundary due to the "less than" portion of the inequality sign.
Answer:
relation of FDs are {a, b, d, h}. From these all but {h}
seem plausibly part of keys. Calculating the closures of likely candidates gives:
{a, b} + = {a b, c, i}
{b, d} + = {b, d, e, f}
{a, d} + = {a, d, g, h, i, j}
{a, b, d} + = {a, b, c, d, e, f, g, h, i, j}
decompose r into 2nf and then 3nf relations shown in attachment.
Step- by-Step Explanation
Explanation is given in the attachment.
Answer:
0.2992 = 29.92% probability of obtaining at least 8 failures.
Step-by-step explanation:
For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
A success is 5 or 6.
A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:
10 normal six sided dice are thrown.
This means that
Find the probability of obtaining at least 8 failures.
This is:
So
Then
0.2992 = 29.92% probability of obtaining at least 8 failures.