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Artyom0805 [142]
3 years ago
9

Which expression is equivalent to −6(23−12)?

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Write an equation of the line that passes through (5,9) and is perpendicular to the line y=-1/3x+1
777dan777 [17]
Perpendicular = opposite sign and reciprocal slope
Slope would be 3
Y = 3x + b, plug in point
9 = 3(5) + b, b = -6
Solution: y = 3x - 6
7 0
2 years ago
Solve 2x – 11 = k for x.
Flura [38]

Answer:

First, you add 11 to the other side of the equals sign. So it would be 2x=k+11. Now, you divide 2 from x and do the same on the other side of the equals sign. so x=  k+11

                ----------

                     2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
At a recent marathon, spectators lined the street near the starting line to cheer for the runners. The crowd lined up 5 feet dee
masha68 [24]

Answer:

29568 people cheered for the runners at the start of the race

Step-by-step explanation:

From the question, the crowd lined up 5 feet deep on both sides of the street for the first mile.

This lined up crowd could be related to a rectangle that is 1 mile long and 5 feet wide.

First, Convert 1 mile to feet

1 mile = 5280 feet

Hence, the length of the rectangle is 5280 feet and the width is 5 feet.

Now, we will determine how many 5 feet by 5 feet square we can get from the 5280 feet by 5 feet rectangle. To do that, we will divide 5280 feet by 5 feet

5280 feet ÷ 5 feet = 1056

Hence, from the rectangle, we can get 1056 5 feet by 5 feet square.

From the question, you estimate that 14 people can comfortably fit in a square that measures 5 feet by 5 feet,

∴ 14 × 1056 people will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

14 × 1056 = 14784 people

This is the amount of people that will comfortably fit in the crowed lined up 5 feet deep on one side of the street for the first mile.

Since the crowd lined up on both sides of the street, then

2 × 14784 people will comfortably fit in the crowed lined up 5 feet deep on both sides of the street for the first mile

2 × 14784 = 29568 people

Hence, 29568 people cheered for the runners at the start of the race.

5 0
3 years ago
From an aeroplane vertically above a straight horizontal plane, the angles of depression of two consecutive kilometres stones on
Airida [17]
You have to build the triangles.

They are such that:
h is the common height
x is the horizontal distance from the plane to one stone
Beta is the angle between x and the  hypotenuse

Then in this triangle: tan(beta) = h / x ......(1)

1 - x is the horizontal distance from the plane to the other stone
alfa is the angle between 1 - x  and h

Then, in this triangle: tan (alfa) = h / [1 -x ] ...... (2)

from (1) , x = h / tan(beta)

Substitute this value in (2)

tan(alfa) = h / { [ 1 - h / tan(beta)] } =>

{ [ 1 - h / tan(beta) ] } tan(alfa) = h

[tan(beta) - h] tan(alfa) = h*tan(beta)

tan(beta)tan(alfa) - htan(alfa) = htan(beta)

h [tan(alfa) + tan(beta) ] = tan(beta) tan (alfa)

h = tan(beta)*tan(alfa) / (t an(alfa)  + tan(beta) )





4 0
3 years ago
John is saving money to buy a game. so far he has saved $12 , which is one-fourth of the total cost of the game. how much does t
Dovator [93]
One fourth of the game cost $3
4 0
3 years ago
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