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kipiarov [429]
3 years ago
6

Complete the tables of values.

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

a=1\\b=\frac{1}{16}\\\\c=\frac{1}{256}\\\\d=1\\e=\frac{4}{9}\\\\f=\frac{16}{81}

Step-by-step explanation:

For the orange table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function f(x)=4^{-x}, then:

For a:

x=0

f(0)=4^0=1

For b:

x=2

f(x)=4^{-2}=\frac{1}{16}

For c:

x=4

f(x)=4^{-4}=\frac{1}{256}

For the blue table:

<em> </em>Substitute the corresponding values of <em>x</em> into the function g(x)=(\frac{2}{3})^x, then:

For d:

x=0

g(x)=(\frac{2}{3})^0=1

For e:

x=2

g(x)=(\frac{2}{3})^2=\frac{4}{9}

For f:

x=4

g(x)=(\frac{2}{3})^4=\frac{16}{81}

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The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
45 times gives me a 100
GaryK [48]

Answer: what’s your question?

Step-by-step explanation:

7 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
Awnswer ASAP I am so stuck
Crazy boy [7]

Answer:

x < - 3

Step-by-step explanation:


7 0
4 years ago
Find all sets of four consecutive integers whose sum is between 95 and 105
Nat2105 [25]
Hello,

Let n-2,n-1,n,n+1 the foru numbers
s=n-2+n-1+n+n+1=4n-2

95<=4n-2<=105
==>97<=7n<=107
==>24.25<=n<=26.75
==>25<=n<=26
if n=25 s=98
if n=26 s=102
7 0
3 years ago
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