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2 years ago

We are getting y=1/2x+1. Help!!!

Mathematics

1 answer:

Strike441 [17]2 years ago

6 0

Answer:

x = 0

y = 1

Step-by-step explanation:

I'm on a school laptop so the pic is blocked, i can not seeee.

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PLS HELP- IM GONNA CRY!!!!!! 30 Points!!!

patriot [66]

Answer:

x^2 - 6x + 8 x - 2

0 8 -2

1 3 -1

2 0 0

3 -1 1

4 0 2

5 3 3

The solutions are in red ⇒ x = 2 and x = 5

8 0

2 years ago

??????????????????????????????

Anna007 [38]

You want to find the time <em>t</em> such that

$\$1000 = \$200 e^{0.04t}$

Divide both sides by $200 :

$\dfrac{\$1000}{\$200} = 5 = e^{0.04t}$

Take the logarithm of both sides:

$\ln(5) = \ln(e^{0.04t}) = 0.04t\ln(e) = 0.04t$

Divide both sides by 0.04 and solve for <em>t</em> :

$t = \dfrac{\ln(5)}{0.04} \approx 40.24 \approx \boxed{40}$

6 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

7 months ago

Erik drives 19.2 miles in 16 minutes.

Kipish [7]

Bruh it clearly says 65 mph so that’s the answer

7 0

3 years ago

Which measurement is the best estimate for the mass of an apple?

Taya2010 [7]

It would be A because an apple can't be 150 g that's way to heavy same for 150kg

3 0

3 years ago

Read 2 more answers