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Alenkasestr [34]
3 years ago
7

Suppose that when your friend was? born, your? friend's parents deposited ?$6000 in an account paying 4.2?% interest compounded

quarterly. What will the account balance be after 19 ?years?
Mathematics
1 answer:
dexar [7]3 years ago
7 0

Answer:

$7317.14

Step-by-step explanation:

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Find the mean, median, mode, and range of the data:<br> {17, 2, 16, 3, 13,5,7,8,9, 11, 5, 2, 1,20}
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Step-by-step explanation:

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What is the inverse of the equation y=3x ?
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y = x/3

Step-by-step explanation:

y = 3x

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Joe is considering pursuing an MBA degree. He has applied to two different universities. The acceptance rate for applicants with
ANEK [815]

Answer:

The probability that Joe will be accepted at one and only one university

P(A n B ) = 0.1

Step-by-step explanation:

Given data the acceptance rate for applicants with similar qualifications is 25% for University A

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The acceptance rate for applicants with similar qualifications is 40% for University B

P(B) = 40% =0.40

<u>Independent events:</u>

let E and F are said to be independent events  then

P(E n F ) = P(E ) P(F)

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7 0
3 years ago
Mingfa says, "My sister and I have $130 altogether. If my mother gives me another
quester [9]

Given:

Total amount of Mingfa and her sister = $130

If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.

To find:

How much money does Mingfa actually have?​

Solution:

Let, Mingfa have $x and her sister has $y initially. Then,

x+y=130                ...(i)

If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.

x+10=3y              ...(ii)

Substitute the value of x from (ii) in (i).

(3y-10)+y=130

4y=130+10

4y=140

Divide both sides by 4.

y=35

Putting y=35 in (i), we get

x+35=130

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Therefore, Mingfa have $95.

8 0
3 years ago
Use tables to show which of these ratios are equivalent: 4/6, 10/25, and 6/15
hoa [83]

Answer:

4/6 and 6/15

Step-by-step explanation:

simplify all fractions to lowest possible.

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