Answer: B
explanation: on y-axis you can see the line touches -8 on graph. for the slope, rise over run could be used 9/9 =1
so y=x-8
QUESTION 3
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles of the kite are congruent.

.
.
.
.
QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;





QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;



QUESTION 7
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles are congruent.

.
.
.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;




QUESTION 9.
The sum of the interior angles of a trapezium is
.
.
.
But the measure of angle M and K are congruent.
.
.
.
.
Answer:
just write the numbers of coins a different way
168cm2
Let r cm be the radius of the balloon, then
<span>2pi(r)=23=>r=23/(2pi) </span>
<span>The surface area= </span>
<span>4pi(r^2)= </span>
<span>4pi[23/2pi)]^2= </span>
<span>(23^2)/pi=168.386 cm^2 </span>
<span>approximately.</span>
Answer:

Step-by-step explanation:
To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?
Solution :
Using metric conversions,
1 kilometer = 1000 meter
1 meter = 100 centimeter
So, 1 kilometer = 100,000 centimeter
and 1 million year = 1,000,000 year


So, 

Therefore, 