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kakasveta [241]
3 years ago
13

When can Eric Wu take pictures of the three Moon features?

Chemistry
2 answers:
Illusion [34]3 years ago
8 0

Answer:

Eric Wu cannot take his pictures on any night because as the Moon orbits the sun different angles of the illuminated half of the Moon is being shown as the days go on. So on some nights the areas of the Moon that Eric Wu wants to take pictures of may not be shown on the Moon because the area is not facing earth.

Explanation:

give me brainly Est

Alik [6]3 years ago
7 0
Eric Wu cannot take his pictures on any night because as the Moon orbits the sun different angles of the illuminated half of the Moon is being shown as the days go on. So on some nights the areas of the Moon that Eric Wu wants to take pictures of may not be shown on the Moon because the area is not facing earth.
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Are atoms the smallest particles we know about, or are there smaller ones?
ZanzabumX [31]

Answer:

subatomic particles are smaller then atoms

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3 years ago
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What cause the ratio of PV/RT to drop below 1 when 1 mole of
pentagon [3]

Answer:

pressure and temperature are directly proportional.

Explanation:

At constant temperature and pressure the volume of a gas is directly proportional to the number of moles of gas. Also given a constant temperature and volume the pressure of a gas is directly proportional to the number of moles of gas.

This means that if V is constant then

P = n (RT/V) then n= PV/RT. As P is increased, T is also increased thereby decreasing the value of n since pressure and temperature are directly proportional.

6 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
How many molecules in 9.18 moles of C11H12O22
Setler [38]

Answer:

55.3 × 10²³ molecules

Explanation:

Given data:

Number of moles of C₁₁H₁₂O₂₂ = 9.18 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

For given data:

9.18 mol × 6.022 × 10²³ molecules /1 mol

55.3 × 10²³ molecules

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helium

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