Answer :
the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.
Explanation:
The answer can be calculated using the formula
Q = mCрΔT
where
Q is the amount of heat required in joules to raise the temperature.
m is the mass of the sample in Kg.
Cp is the specific heat of the sample in J/Kg°C.
ΔT is the change in temperature required.
Here, m = 49.5-gram = 0.0495 kg
Cp = 4.18 J/Kg°C (for water)
T₁ = 22°C ; T₂ = 66°C
ΔT = 66 - 22 = 44
Substituting values in Q = mCрΔT
Q = (0.0495)(4.18)(44)
Q = 9.104 J
In here Oxygen is the central atom. It makes two bonds with
Cl and has two lone pairs. Since, the shape is bent and the hybridization is
sp3. Molecular geometry is a bit dissimilar from hybridization. Hybridization
is reliant on the number of bonds and lone pairs. Since O has two bonds with
Cl, its hybridization is sp3. It is like is this: 1 lone pair/bond = s. 2 lone
pairs/bond = sp 3 lone pairs/bonds = sp2, etc. molecular geometry, you count
the number of bonds and lone pairs. This has two bonds and 2 lone pairs so if
they were all bonds, the molecule would be tetrahedral.
Answer:
Starting at 1 to 2 months of age, the baby will receive vaccinations
Explanation:
have a wonderful day!
Answer:
The temperature would be 194, 8 K.
Explanation:
We use the formula:
PV=nRT --> T=PV/nR
T= 0,500 atm x 28, 6 L/ 0,895 mol x 0,082 l atm /K mol
<em>T= 194,8494345 K</em>
5.8 is 11.2% of what number
51.786 grams
