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____ [38]
2 years ago
6

Help asap plzzz I NEED HELP !!!!!!!!

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
4 0

Answer:

1520.5 in^2

Step-by-step explanation:

Surface area=2*pi*r^2+2*pi*r*h=2*pi*r*(r+h)=2*pi*11*22=1520.5 in^2

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Which angles are pairs of corresponding angles? Check all that apply
AleksAgata [21]

Answer:

B and D people. Your welcome.

Step-by-step explanation:

6 0
3 years ago
Can anyone help please
Akimi4 [234]

Answer: X = 27

Step-by-step explanation: If we observe very closely, we have two similar triangles in the diagram. The first one is ABC and the other triangle is EDC. Also take note that angle ACB in the first triangle is equal in measurement to angle ECD (45 degrees) in the other triangle, (Opposite angles).

Hence in triangle ECD, we have identified two angles so far which are angle 2x + 10 and angle 45. Same applies to triangle ABC, we already have two angles which are, 3x - 10 and 45.

However angle D in the second triangle is equal in measurement to angle B in the first triangle

(Alternate angles).

Hence we have a third angle in triangle ABC which is

Angle B = 2x + 10.

Therefore 3x - 10 + (2x + 10) + 45 = 180

(Sum of angles in a triangle)

3x - 10 + 2x + 10 + 45 = 180

By collecting like terms we now have

3x + 2x = 180 + 10 - 10 - 45

5x = 135

Divide both sides by 5,

x = 27

8 0
2 years ago
Radius = 11 cm.; Height = 10 cm.
Fittoniya [83]

Answer:

3801.32 {cm}^{3}

Step-by-step explanation:

V=π {r}^{2} h \\ =π· {11}^{2} ·10 \\ ≈3801.3271

5 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
2 years ago
How many calories u will burn in 1 minute while biking
IrinaK [193]

Answer: 255 calories hope this helps :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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