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3 years ago

Tom sells baseball cards at 10 for 35 cents. Is that a better deal than 12 for 40 cents?

2 answers:

8 0

1 case
35c : 10 = 3,5c
2 case
40c : 12 = 3,(3)c

3,(3)c < 3,5c

Anwers
First option is a better deal than second version.

AVprozaik [17]3 years ago

7 0

For either one of the deals, just find what one card equals and times it by how many cards the other equation has.

e.g. 0.35 cents divide by 10 = 0.035. And now, you times it by 12 since the other deal is 12 cards for 40 cents.

0.035 x 12 = 0.48

So, 10 cards for 35 cents is not the better deal.

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2 years ago

Read 2 more answers

Deja has two baskets of berries. One of the baskets has 3 3/8 pounds of berries and the other basket has 2 7/8 pounds of berries

ElenaW [278]

Answer:

(b) The number of pounds of berries each person would receive is $1\frac{5}{8}$ pounds.

Step-by-step explanation:

The amount of berries in first basket = 3 3/8 pounds

Now, $3\frac{3}{8} = 3+\frac{3}{8} = 3 + 0.375 = 3.375$

So, the amount of berries in first basket = 3.375 pounds

The amount of berries in second basket = 2 7/8 pounds

Now, $2\frac{7}{8} = 2+\frac{7}{8} = 2 + 0.875 = 2.875$

So, the amount of berries in second basket = 2.875 pounds

Now, the total berries = Berries in ( First + Second) basket

= 3.375 pounds + 2.875 pounds

= 6.25 pounds

So, the number of pounds each person would have = $\frac{\textrm{Total weight of viable berries}}{\textrm{4}} = \frac{6.25}{4} = 1.5625$

Now, $1.5625 = 1 + 0.5625 = 1 + \frac{5625}{10000} = 1 + \frac{5}{8} = 1\frac{5}{8}$

So, the number of pounds of berries each person would receive is $1\frac{5}{8}$ pounds.

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3 years ago

How does Mr. Peters get to ask for three wishes?

satela [25.4K]

Answer:

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Step-by-step explanation:

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3 years ago

What are the standard measurement sizes for dry measuring cups?

swat32

Answer:

The standard 4 measuring cup sizes are: 1 cup, 1/2 cup, 1/3 cup and 1/4 cup. With those four cup sizes you can measure dry ingredients for any recipe.

Step-by-step explanation:

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3 years ago

Enter the explicit rule for the sequence

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Let's take a look at the first few numbers in the sequence based on the given rule:

$a_{1}=6\\ a_{2}= \frac{1}{4}(6)\\ a_3= \frac{1}{4}\big( \frac{1}{4}\big)6= \big(\frac{1}{4}\big)^2(6)\\ a_{4}= \frac{1}{4} \big(\frac{1}{4}\big)^26= \big(\frac{1}{4}\big)^3(6)$

Inspecting this pattern it seems like the power $\frac{1}{4}$ is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be $\big(\frac{1}{4} \big)^{n-1}$ . We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

$a_n=6\big( \frac{1}{4} \big)^{n-1}$

Where $a_n$ is the nth number in our sequence.

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3 years ago