Answer:
See explanartions below
Step-by-step explanation:
Given the coordinates A(-6,3) B(0,5) C(2,-1)
We first need to get the slope of AB, BC and AC
For AB;
A(-6,3) B(0,5)
Mab = 5-3/0-(-6)
Mab = 2/6
Mab = 1/3
For BC;
B(0,5) C(2,-1)
Mbc = -1-5/2-0
Mbc = -6/2
Mc = -3
For AC:
A(-6,3) C(2,-1)
Mac = -1-3/2-(-6)
MAc = -4/8
Mac = -1/2
Taking the product of Mab and Mbc
Mab * Mbc = 1/3 + -3
Mab * Mbc = -1
<em>Since the product of Mab and Mbc is -1, hence AB abd BC are perpendicular showing that one of the angle of triangle ABC is 90 degrees</em>
Answer:
28
Step-by-step explanation:
12+[(15-5)]+(9-3)]
PEMDAS
Parentheses first
12+[(10)]+(6)]
Then add
12+10+6
The answer is -13.
Solution:
= |-4b - 8| + |-1 - b^2| + 2b^3
= |-4(-2) - 8| + |-1 - -2^2| + 2(-2)^3
= |8-8| + |-1+4| + 2(-8)
= |0| + |3| + (-16)
= -13
