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mojhsa [17]
3 years ago
5

Help please, kind of confused

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

Step-by-step explanation:

Yikes. This is quite a doozy, so pay attention. We will begin by factoring by grouping. Group the first 2 terms together into a set of parenthesis, and  likewise with the last 2 terms:

(2d^4+6d^3)-(18d^2-54d) and factor out what's common in each set of parenthesis:

2d^3(d+3)-18d(d+3). Now you can what's common is the (d + 3), so factor that out now:

(d+3)(2d^3-18d) BUT in that second set of parenthesis, we can still find things common in both terms, so we continue to factor that set of parenthesis, carrying with us the (d + 3):

(d+3)2d(d^2-9) BUT that second set of parenthesis is the difference of perfect squares, so we continue factoring, carrying with us all the other stuff we have already factored:

(d+3)2d(d+3)(d-3). That's completely factored, but it's not completely simplified. Notice we have 2 terms that are identical: (d + 3):

2d(d+3)^2(d-3) is the completely factored and simplified answer, choice 3)

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Answer:

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Step-by-step explanation:

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3 years ago
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First, we need to find the LCD (Least Common Denominator) so we can subtract them much easier.

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Answer:

Step-by-step explanation:

Alright, lets get started.

The given expression is :

(\frac{r}{32s} )^{\frac{8}{5} }

It could be written as

(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{32} )^{\frac{8}{5} }

32 could be written as 2^{5}

So, replacing that in our expression

(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{2^{5} } )^{\frac{8}{5} }

(\frac{r}{s} )^{\frac{8}{5} }*(\frac{1}{2} )^{5*\frac{8}{5} }

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\frac{1}{256}*(\frac{r}{s} )^{\frac{8}{5} }

This is the simplified form of given expression.  :  Answer

Hope it will help :)




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Answer:

Hi there

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