Question

An object is traveling around a circle with a radius of 20 meters. If in 10 seconds a central angle of 1/5 radian is swept out, what is the linear speed of the object?

Answer 1

The linear speed of the object is the ratio between the measure of the arc it had traveled and the time. For the length of the arc,
                     2π x (20 m) x (0.2 rad/ 2π rad) = 4 meters
Divide this by the time, 10 s. Thus, the linear speed is equal to 0.4 m/s. 

Answer 2

Answer:

The linear speed is 0.4 m/s

Step-by-step explanation:

Given,

The radius of the circle = 20 meters,

The central angle made by the object that travelling around the circle = $\frac{1}{5}$ radian,

So, the distance covered by the object = The radius of the circle × Central angle made by the object ( in radians )

$=20\times \frac{1}{5}$

$=4\text{ meters}$

Now, the time taken by the object in travelling = 10 seconds,

$\text{Speed}=\frac{\text{Distance}}{\text{Time}}$

Hence, the linear speed of the object = $\frac{4}{10}$

= 0.4 m/s