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3 years ago

9

Let f(x) =3x-3 and g(x) = 21evaluate(-25)(-1)

1 answer:

NISA [10]3 years ago

7 0

Use photo math , that will help a lot!!

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Are the compositions of f(x) = 1 and g(x) = 2 commutative? Why or why not?

AlladinOne [14]

Answer:

first option

Step-by-step explanation:

They are cumulative because they are constant functions.

4 0

2 years ago

What is the value of x, when x2 + 5 = 21?

djverab [1.8K]

Hey there!

$\bold{x^2+5=21}$
<em>Firstly, subtract by the number $\bold{5}$ on each of your sides</em>
$\bold{x^2+5-5=21-5}$
$\bold{Cancel:5-5}$ because it gives us the result of $\bold{1}$
$\bold{Keep:21-5}$ because it equals: $\bold{16}$
$\bold{x^2=16}$
<em>Nextly, we have to take our square root </em>
$\bold{x=}$ ± $\bold{\sqrt{16}}$
<em>Solve the square root and you have found your answer</em>
<em> $\boxed{\boxed{\bold{Answer:x=4[or]x=-4}}}$ $\bold{\checkmark}$ </em>

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

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3 years ago

Quadrilateral ABCD is dilated by a scale factor of 1/3 centered around (1,2). Which statement is true about the dilation

morpeh [17]

Answer:

I cannot help answer this question if you don't add the statements...

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Explain how to use the distributive property to find the product 3 x 4 1/5

NikAS [45]

Answer:

12.6

Step-by-step explanation:

The answer is 12.6 and here is the explanation of using the Distributive Property. Because we are multiplying a whole number by a mixed number, we have to multiply the whole number by the whole number in the mixed number and then multiply the whole number by the fraction. In this case, we have 3 x 4 1/5. We multiply 3x4=12 first, and then we multiply 3x1/5 to get 0.6. 12+0.6=12.6. Hope it helps!

5 0

3 years ago

Please help!!!! <br><br> If f(1) = 2 and f(n+1) = f(n)^2 – 3 then find the value of f(3).

Black_prince [1.1K]

Answer:

The value of f(3) is -2.

Step-by-step explanation:

This is a recursive function. So

$f(1) = 2$

Now, we find f(2) in function of f(1). So

$f(1+1) = f(1)^2 - 3$

$f(2) = f(1)^2 - 3 = 2^2 - 3 = 1$

Now, with f(2), we can find the value of f(3).

$f(2+1) = f(2)^2 - 3$

$f(3) = f(2)^2 - 3 = 1^2 - 3 = -2$

The value of f(3) is -2.

4 0

3 years ago