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2 years ago

You are given two algebraic equations, y = 3x, and 2y = x + 20. Solve for x and y.

Mathematics

1 answer:

Yuri [45]2 years ago

7 0

Answer:

x= -4 & y=-12

Step-by-step explanation:

multiply y=3x by 2

giving you 2y=6x

subtracting 2y=x+20 from 2y =6x

=> 5x=-20

dividing through by 5

=> x=-4

put x=-4 into y=3x

=> y=3(-4)

y=-12

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The temperature at noon on Monday

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Answer:

There was a 5% change

Step-by-step explanation:

On Monday, the temperature was 80.

On Tuesday, the temp was 77

On Wednesday, the temp was 84

there was a difference of 4

4 is 5% of 80

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2 years ago

Lines k and p are perpendicular, neither is vertical and p passes through the origin. Which is greater? A. The product of the sl

AlladinOne [14]

What do we know about those two lines?

They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
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[draw it if this is not obvious and ask where does it cross the y axis]
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Answer A

4 0

3 years ago

A bad punter on a football team kicks a football approximately straight upward with an initial velocity of 89 ft/sec.

Andrej [43]

Answer:

See below

Step-by-step explanation:

Vertical velocity will be affected by gravity in this scenario

df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2

df = 4 + 89 t - 1/2 (32.2) t^2 df = height

On the way up and the way down, the ball may reach height of 102.2125 ft :

102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:

-16.1 t^2 + 89t - 98.2125 =0

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6 0

1 year ago

2 u + 12 < 23 0,1 d + 8 > 0 3 - 4 r > 7 13 < 2 z + 3 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

The question is

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

3 years ago

Csc A - sin A = A. (cos^2A) / (sinA) B. (1 - sinA) / (sinA) C. (1 - sinA) / (cosA)

julsineya [31]

Answer:

A) $\frac{cos^2A}{sinA}$

Step-by-step explanation:

$cscA-sinA\\\\\frac{1}{sinA}-sinA\\ \\\frac{1}{sinA}-\frac{sin^2A}{sinA}\\ \\ \frac{1-sin^2A}{sinA}\\ \\\frac{cos^2A}{sinA}$

4 0

2 years ago

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