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Gre4nikov [31]
2 years ago
11

Solve 8 = 2^x + 4 x=-4 x=-1 x=0 x=7

Mathematics
2 answers:
velikii [3]2 years ago
8 0

Answer:

x = -1

Step-by-step explanation:

marin [14]2 years ago
5 0

Answer:

x=-1

Step-by-step explanation:

because 2^3 is 8

and when you do -1+4 you get left with 3

so x=-1

You might be interested in
The zeros of f(x)= 3x^3+16x^2+18x-4
Otrada [13]

After trial and error, you discover that - 2 works.

-2 || 3   16    18   -4

           -6   -20    4

====================================

      3    10  - 2    0

What you have left is a quadratic

3x^2 + 10x - 2 You can just use the quadratic formula to solve for the other 2 roots.

x1 =  [ - 10 +/- sqrt(10^2 - 4*3*(-2) ) ] / 6

x1 =  [ -10 +/- sqrt (100 + 24) ) /6

x1 =  [ - 10 +/- sqrt(124) ) / 6

x1 = [ - 10 +/- 11.14 ] / 6 = 0.1893

x2 = [ - 21.14 ] / 6 = - 3.522

Answer

x1 = - 2

x2 = 0.1893

x3 = - 3.522

4 0
3 years ago
Which relationship has a zero slope?
Kay [80]
A Horizontal line means you get a slope of zero
7 0
3 years ago
Read 2 more answers
Can -111/-80 be simplified? If so, what can it be simplified to and how?
jeka94

Answer:

no

Step-by-step explanation:

i cant be simplified

5 0
2 years ago
Tamara is planting bushes around her house. So far today she has planted 5 bushes and she wants to plant at least 12 bushes toda
bixtya [17]

Answer:

b+5\geq 12

Step-by-step explanation:

Given:

Number of bushes planted = 5

Minimum number of bushes to be planted = 12

Let the number of bushes planted after planting 5 bushes be b.

Since, Tamara has already planted 5 bushes, total number of bushes planted is given as:

b+5

Now, as per question, total number of bushes should be 12 or greater than 12.

Therefore, b+5\geq 12.

6 0
2 years ago
Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru
jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time (t_{T}) that Keenan will be from home is the sum of run (t_{R}), hang out (t_{H}) and walk times (t_{W}), measured in hours:

t_{T} = t_{R}+t_{H}+t_{W}

If Keenan runs and walks at constant speed, then equation above can be expanded:

t_{T} = \frac{x_{R}}{v_{R}}+t_{H}+ \frac{x_{W}}{v_{W}}

Where:

x_{R}, x_{W} - Run and walk distances, measured in miles.

v_{R}, v_{W} - Run and walk speeds, measured in miles per hour.

Given that x_{R}=x_{W} = 2.5\,mi, v_{R} = 6\,\frac{mi}{h}, v_{W} = 4\,\frac{mi}{h} and t_{H} = 0.75\,h, the total time is:

t_{T} = \frac{2.5\,mi}{6\,\frac{mi}{h} } + 0.75\,h+\frac{2.5\,mi}{4\,\frac{mi}{h} }

t_{T} = 1.792\,h (1\,h\,48\,m)

Kennan will be from home approximately an hour and 48 minutes.

7 0
3 years ago
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