according to the question
3x-1=0
3x=1
x=⅓
so
f(x)=18x³+x-1
f(⅓)=18.(⅓)³+⅓-1
f(⅓)=18.⅓.⅓.⅓+⅓-1
f(⅓)=6.⅑+⅓-1
f(⅓)=⅔+½-1
f(⅓)=0
<h3>therefore</h3><h3> the remainder is 0</h3>
The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:
s(x) = x - 7
t(x) = 4x^2 - x + 3
(t*s)(x) = t(s(x)) = t(x - 7) = <span>4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3
The correct result would be </span>4(x – 7)2 – (x – 7) + 3.
Answer:
g = 3
Step-by-step explanation:
12−1−7−g=1
Step 1: Simplify both sides of the equation.
12−1−7−g=1
12+−1+−7+−g=1
(−g)+(12+−1+−7)=1(Combine Like Terms)
−g+4=1
−g+4=1
Step 2: Subtract 4 from both sides.
−g+4−4=1−4
−g=−3
Step 3: Divide both sides by -1.
−g
/−1
=
−3
/−1
g=3
I think this might help but sorry if it does not but I hope it does :) :D - https://learnzillion.com/lesson_plans/5701-writing-an-explicit-formula-for-the-graph-of-an-exponential-relationship/
