Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.
Quick note
We can use a formula to find out the sum of an arithmetic series:
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
Answer:
y = 2/3x + 3
Step-by-step explanation:
In order to put it in slope intercept form (y = mx + b), y needs to be isolated.
Add 2x to both sides:
-2x + 3y = 9
3y = 2x + 9
Then, divide both sides of the equation by 3.
3y = 2x + 9
y = 2/3x + 3 is the equation in slope intercept form
1/sin^2x-1/tan^2x=
1/sin^2x-1/ (sin^2x/cos^2x)<<sin tan= sin/cos>>
= 1/sin^2x- cos^2x / sin^2x
= (1- cos^2x) / sin^2x <<combining into a single fraction>>
sin^2 x / sin^2x <<since 1- cos^2 x sin^2 x
=1
this simplifies to 1.
Answer:
4^y = x + 3
2^y = x + 2
Step-by-step explanation:
log_4(x + 3 ) = log_2 (2 + x )
log_4( x + 3 ) = y
log_2 (2 + x ) = y
4^y = x + 3
2^y = x + 2