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2 years ago

15

Find the remainder when the function is

1 answer:

prisoha [69]2 years ago

4 0

according to the question

3x-1=0

3x=1

x=⅓

so

f(x)=18x³+x-1

f(⅓)=18.(⅓)³+⅓-1

f(⅓)=18.⅓.⅓.⅓+⅓-1

f(⅓)=6.⅑+⅓-1

f(⅓)=⅔+½-1

f(⅓)=0

<h3>therefore</h3><h3> the remainder is 0</h3>

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