Answer:
Step-by-step explanation:
The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function
g(x,y) = sin(π(x−5y)
∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))
(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]
(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]
∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j
∇g = π [cos (π(x−5y))] [î - 5j]
So, the question requires a direction vector and a point to fully evaluate this directional derivative now.
Answer: It will land on the bush after 1.25 seconds.
First, we will start with what we are given the equation: h(t) = -16t^2 + 30
Now, we should input a 5 for the h(t) because we want the seconds that will give us a height of 5 seconds.
5 = -16t^2 + 30
Solve the equation:
0 = -16t^2 + 25
To solve this, you could use the quadratic formula or factor out a -1 and you will have the difference of two squares.
Either way the answer is 1.25 seconds.
Answer:
11x+50
Step-by-step explanation:
Answer:
2. 1/2
Step-by-step explanation:
slope is rise over run
y2-y1/x2-x1
7-5/6-2 = 2/4 = 1/2
